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omeli [17]
2 years ago
10

Does this graph represent a function? Why or why not

Mathematics
2 answers:
grandymaker [24]2 years ago
7 0

Answer:

  B.  yes, it passes the vertical line test

Step-by-step explanation:

A vertical line intersects the graph in at most 1 place. That test passes, so the graph represents a function.

_____

A function maps any given x-value to only one y-value.

viktelen [127]2 years ago
5 0

Answer:

C

Step-by-step explanation:

It passes the horizontal line test

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Which number line model shows 8 x 1/2
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Step-by-step explanation:

6 0
3 years ago
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Is floor(x) periodic?
diamong [38]

If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.

The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.

Conclusion: The function floor(x) is <u>not</u> periodic.

4 0
4 years ago
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If y varies inversely as the square of x, and y = 1/8 when x = 1, find y when x = 5.
Kisachek [45]
Y = k / x² ( y varies inversely as the square of x ) 
y = 1/8 when x = 1:
1/8 = k / 1²
8 k = 1
k = 1/8
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6 0
3 years ago
Factor out the coefficient of the variable term.
aivan3 [116]

Given:

The expression is

\dfrac{1}{2}n-\dfrac{1}{2}

To find:

The factored form of given expression after factor out the coefficient of the variable term.

Solution:

We have,

\dfrac{1}{2}n-\dfrac{1}{2}

Here, the coefficient of variable n is \dfrac{1}{2}.

It can be written as

=\dfrac{1}{2}\times n-\dfrac{1}{2}\times 1

Taking out \dfrac{1}{2} as common factor, we get

=\dfrac{1}{2}(n-1)

Therefore, the factored from of given expression is \dfrac{1}{2}(n-1).

6 0
3 years ago
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