<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
the opposite or addictive increase of 5x is -5x.
the opposite or addictive increase of 5x + 8 is -5x -8.
Answer
Answer= 4
Step-by-step explanation:
The answer is 4 because for the median you have to put the numbers from smallest to largest.
When you have done that you have to find the middle number which in this case is 4.
Hope that helps you
