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masya89 [10]
3 years ago
10

Five and 1/3÷2 2/3 simplified

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

5 1/3 ÷ 2 2/3

Write both mixed fractions (whole number in front of fully-reduced fraction) as improper fractions (numerator is larger than denominator).

5 1/3 = 16/3

2 2/3 = 8/3

16/3 ÷ 8/3

When dividing, switch the numerator and the denominator of the fraction after the division sign and change the division sign to a multiplication sign.

16/3 x 3/8

Multiply.

16/8

Divide by 8.

2

Hope this helps! :)

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PLEASE RESPOND! !!
cestrela7 [59]

Answer:

36/132

Step-by-step explanation:

36/132, .27, 27%...

6 0
3 years ago
Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to
mart [117]
I would approach the problem like this:

1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3

in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
3 0
3 years ago
In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

4 0
3 years ago
Under her cell phone plan, Peyton pays a flat cost of $48 per month and $3 per gigabyte. She wants to keep her bill at $60.60 pe
Ad libitum [116K]

Answer: 4.20 gigabyte

Step-by-step explanation:

Based on the information given in the question, the equation that can be used to determine the the number of gigabytes of data Peyton can use while staying within her budget will be:

48 + 3g = 60.60

3g = 60.60 - 48

3g = 12.60

g = 12.60/3

= 4.20

The number of gigabytes of data is 4.20g

4 0
3 years ago
Read 2 more answers
How much would it be if 2 1/4 is tripled
Tcecarenko [31]
If you mean added together 3 times then it would be 6 3/4 and just in case this sounds rude I do not want it to be.
4 0
3 years ago
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