Complete Question
A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.
Answer:
The value of the 16th percentile is 
The range for the middle 3 standard deviation is 
Step-by-step explanation:
From the question we are told that
The mean is 
The median is 
The mode is 
The standard deviation is 
Generally the 16th percentile is mathematically represented as
![P(x)= P(\frac{X - \mu }{ \sigma } \le \frac{x- 25 }{5} ) = 0.16[/teGenerally [tex]\frac{X - \mu}{\sigma } = Z(The \ standardized \ value \ of \ X )](https://tex.z-dn.net/?f=P%28x%29%3D%20P%28%5Cfrac%7BX%20%20-%20%20%5Cmu%20%7D%7B%20%5Csigma%20%7D%20%20%20%5Cle%20%5Cfrac%7Bx-%2025%20%7D%7B5%7D%20%29%20%3D%200.16%5B%2Fte%3C%2Fp%3E%3Cp%3EGenerally%20%20%5Btex%5D%5Cfrac%7BX%20-%20%20%5Cmu%7D%7B%5Csigma%20%7D%20%20%3D%20%20Z%28The%20%20%5C%20%20standardized%20%5C%20%20value%20%5C%20of%20%20%5C%20X%20%20%29)
So

Now from the normal distribution table the z-score of 0.16 is
z = -1

=> 
=> 
=> 
=> 
The range for the middle 3 standard deviation is mathematically represented



Answer:
jzjshdjakamkw wjejsna ja w iw wiw wkwjwkęi
Wow. 16,000 a month? Where does he work? Can I come intern?
But anyways, 1/4 of $16000 is $4000 so he has $12,000 left. 3/10 of $12000 is $3600 so he has $8400 left. 5/21 of $8400 is $2000 so therefore he has $6400 left.
The answer is C- Berthas cake weighs 463 grams more than Jessups cake
a)
(59, 76) and (65, 100)
y - y1 = m(x - x1)
y - 100 = (100-76)/(65 - 59)(x - 65)
y - 100 = (24/6)(x - 65)
y - 100 = 4(x - 65)
y - 100 = 4x - 260
y = 4x - 160
b)
x = 90
y = 4x - 160
y = 4(90) - 160
y = 360 - 160
y = 200
200 chirps per minute
c)
y = 120
y = 4x - 160
120 = 4x - 160
280 = 4x
x = 70
70 degrees