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luda_lava [24]
3 years ago
5

Equations and Inequalities 2x-4=4x-5​

Mathematics
2 answers:
ankoles [38]3 years ago
7 0

2x−4=4x−5
(2x−4)+(4−4x)=(4x−5)+(4−4x)
2x−4+4−4x=4x−5+4−4x
2x−4x−4+4=4x−4x−5+4
−2x=−1

Answer: x=1/2
Zina [86]3 years ago
3 0
Much easier way to do it:
2x-4=4x-5
-2x -2x
-4=2x-5
+5 +5
1=2x
2
x= 1/2
Step By Step in words:
Step1: In order to get the x's on both sides, subtract 2x from both sides
Step2 : Now to get the x by itself, do the opposite operation of -5 and add five to both sides
Step 3: Final Step to get the x by itself, do the opposite operation of 2 times x. Divide 2x by 2 and 1 by 2
Which gives you 1/2
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Step-by-step explanation:

<u>Problem 1</u>

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<u>Problem 2</u>

<u />cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)

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<u>Problem 3</u>

<u />2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0

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