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Vinil7 [7]
2 years ago
14

A bag contains 10 marbles: 6 are green, 2 are red, and 2 are blue. Frank chooses a marble at random, and without putting it back

, chooses another one at random. What is the probability that the first marble is green and the second is red? Write your answer as a fraction in simplest form.
Business
2 answers:
weqwewe [10]2 years ago
7 0
You have to do a tree diagram I can't show u but all I can tell u is u have to add all the marbles together to make 20 and the first part to the question is 6/20 but u have to take away 2/20 overall the answer could be 3/20 averaging it but this is estimated so u have to draw a tree diagram to make sure it's correct
NemiM [27]2 years ago
3 0
For the green it would be 6/10 and the red 2/10
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Cleveland Corporation acquired a machine for $42,000 and has recorded depreciation for two years using the straight line method
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Answer:

The book value of the machine at the end of year 2 is $35,000

Explanation:

Straight line method depreciates the asset on its useful life after deducting salvage value from the cost of the asset.

Depreciation per year = ( Cost of Machine - Residual Value ) / Useful life

Depreciation per year = ( $42,000 - $7,000 ) / 10 years

Depreciation per year = $3,500 per year

Book value of machine at the end of year 2 = $42,000 - ( $3,500 x 2 )

Book value of machine at the end of year 2 = $42,000 - $7,000

Book value of machine at the end of year 2 = $35,000

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2 years ago
A fast-food restaurant has determined that the chance a customer will order a soft drink is 0.90. The proba- bility that a custo
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Answer:

(a) The probability that the order will include a soft drink and no fries is 0.45.

(b) The probability that the order will include a hamburger and fries is 0.48.

Explanation:

Let the events be denoted as follows:

S = an order of soft drink

H = an order of hamburger

F = an order of french fries.

Given:

P (S) = 0.90

P (H) = 0.60

P (F) = 0.50

(a)

It is provided that the event of ordering a soft drink and fries are independent.

If events A and B are independent then the probability of event (A ∩ B) is:

P(A\cap B)=P(A)\times P(B)

Compute the probability that the order will include a soft drink and no fries as follows:

P(S\cap \bar F)=P(S)\times P(\bar F)\\=P(S)\times[1-P(F)]\\=0.90\times (1-0.50)\\=0.45

Thus, the probability that the order will include a soft drink and no fries is 0.45.

(b)

It is provided that the conditional probability that a customer will order fries given that he/she has already ordered a hamburger as, P (F|H) = 0.80.

The conditional probability of an event B given another event A has already occurred is:

P(B|A)=\frac{P(A\cap B}{P(A)}

Compute the probability that the order will include a hamburger and fries as follows:

P(F|H)=\frac{P(H\cap F)}{P(H)}\\P(H\cap F)=P(F|H)\times P(H)\\=0.80\times 0.60\\=0.48

Thus, the probability that the order will include a hamburger and fries is 0.48.

6 0
3 years ago
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