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seraphim [82]
3 years ago
15

- 1/2 x ( - 1/8 ) - 3/4

Mathematics
2 answers:
sasho [114]3 years ago
7 0
-AURORALIA00- is right

Ksenya-84 [330]3 years ago
5 0

-11/16

(Decimal: -0.6875)

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Rewrite in simplest radical form 1/x^-3/6
VladimirAG [237]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad

\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\quad \\
% rational negative exponent
a^{-\frac{{ n}}{{ m}}} =
 \cfrac{1}{a^{\frac{{ n}}{{ m}}}} \implies \cfrac{1}{\sqrt[{ m}]{a^{ n}}}
\\ \quad \\ \quad \\

%  radical denominator
\cfrac{1}{\sqrt[{ m}]{a^{ n}}}= \cfrac{1}{a^{\frac{{ n}}{{ m}}}}\implies a^{-\frac{{ n}}{{ m}}}\qquad thus\\
----------------------------\\

\\ \quad \\

\bf 
\\ \quad \\

\cfrac{1}{x^{-\frac{3}{6}}}\implies \cfrac{1}{x^{-\frac{1}{2}}}\implies \cfrac{1}{\frac{1}{x\frac{1}{2}}}\implies \cfrac{1}{1}\cdot \cfrac{x^{\frac{1}{2}}}{1}
\\ \quad \\
x^{\frac{1}{2}}\implies \sqrt{x}
4 0
4 years ago
Which of the following represents the set of possible rational roots for the polynomial shown below?
andriy [413]
You need to work out the variables of 20 (the last number) first: 
1, 2, 4, 5, 10, 20 
Lets call these folks "p" 
At that point you need to work out the components of the main coefficient (the number before the most astounding force of x): 
1 
Lets call this person "q" 
At that point you need to make all the conceivable divisions you can with: 
±p/q 
Since q is only 1, we are fortunate, so the conceivable normal roots are: 
±1/1,±2/1,±4/1,±5/1.±10/1,±20/1
3 0
3 years ago
Read 2 more answers
Follow all directions in the problem below.
kirill115 [55]

Answer: 110 test were purchased

Step-by-step explanation:

Set P = number of packets of 10 test

Total cost = $30 + $11 x P = $151

$11xP = $151 - $30 = $121

P = $121/$11 = 11 packets were purchased

Test purchased = 11packets x 10 test/packet = 110 test were purchased

Answer: 110 test were purchased

<h3><em>Spymore</em></h3>
4 0
3 years ago
Solve. 3 1/3 - 1 2/3 =?
kifflom [539]

Step-by-step explanation:

First you change them to improper fractions. 10/3 and 5/3

Next you subtract 10 and 5 which is obviously 5

Then you have 5/3 turning that to a mixed number makes it 1 2/3

Hope this helps!

8 0
3 years ago
Read 2 more answers
*WILL MARK BRAINLIEST!!!!!!*
Nuetrik [128]

Answer:

y=1

Step-by-step explanation:

The value of y where the function is undefined

7 0
4 years ago
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