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3 years ago

A map is drawn to scale so that 1.2 cm represents 30 miles.How many miles does 1.4 cm represent?

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

40 miles hope this help[s

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| 7x28 = (748) + ( 7 *__) =

masya89 [10]

Answer:

-23

Step-by-step explanation:

i dont know

3 0

3 years ago

For one full week, Cheng spent $12.50 per day on lunch. Write a multiplication expression using integers to show the overall imp

grin007 [14]

Answer is :a x 12.50= 87.5

3 0

3 years ago

What is the solution to the equation 1 over 2 multiplied by n equals 7?

Minchanka [31]

Answer:

n=14

Step-by-step explanation:

multiply both sides by two to get rid of 1/2 and you find n=14

7 0

3 years ago

Read 2 more answers

Rewrite this non-statistical question as a statistical question. How many minutes do I exercise each day?

stira [4]

Answer:

The statistical question should be

"how many minutes do I exercise on each day of the week" and "how many minutes do I exercise each day of the week whilst there is background music"

Step-by-step explanation:

Here we have the non statistical question, how many minutes do I exercise each day

We note that a statistical question is one in which there are are different variety answers, where the distribution and the inclination of the the answers is sought

Therefore, statistically, we should ask, "how many minutes do I exercise on each day of the week" or "how many minutes do I exercise each day of the week whilst there is background music".

8 0

3 years ago

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

5 0

2 years ago