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Ivanshal [37]
3 years ago
12

3. Whether an accident scene is safe or not, you should first take action to help any victims.

Engineering
1 answer:
olga_2 [115]3 years ago
7 0
A (sorry have to make my answer 20 characters long so just ignore this)
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The volume of 1.5 kg of helium in a frictionless piston-cylinder device is initially 6 m3. Now, helium is compressed to 2 m3 whi
coldgirl [10]

Answer:

The initial temperature will be "385.1°K" as well as final will be "128.3°K".

Explanation:

The given values are:

Helium's initial volume, v₁ = 6 m³

Mass, m = 1.5 kg

Final volume, v₂ = 2 m³

Pressure, P = 200 kPa

As we know,

Work, W=p(v_{2}-v_{1})

On putting the estimated values, we get

⇒            =200000(2-6)

⇒            =200000\times (-4)

⇒            =800,000 \ N.m

Now,

Gas ideal equation will be:

⇒  pv_{1}=mRT_{1}

On putting the values. we get

⇒  200000\times 6=1.5\times 2077\times T_{1}

⇒  T_{1}=\frac{1200000}{3115.5}

⇒       =385.1^{\circ}K (Initial temperature of helium)

and,

⇒  pv_{2}=mRT_{2}

On putting the values, we get

⇒  200000\times 2=1.5\times 2077\times T_{2}

⇒  T_{2}=\frac{400000}{3115.5}

⇒       =128.3^{\circ}K (Final temperature of helium)

3 0
3 years ago
A. Name the major strengthening mechanisms in metals and explain the working principle under each mechanism.Give the relevant eq
Sever21 [200]

Answer:

a) Solid solution strengthening and alloying,  Precipitation hardening, work hardening

b) Absence of enough  crystallographic misalignment in the grain boundary region for a small-angle

Explanation:

<u>A) strengthening mechanism</u>

i) Solid solution strengthening and alloying:

In solid solution strengthening and alloying mechanism there is an addition of one atom of solute to another during this process, there might be substitution of interstitial point defect in crystal

also the shear stress required can be represented as:  Δz = Gb√Ce^3/2

where : C = solute concentration , e = strain on material

ii) Precipitation hardening:

During precipitation hardening the alloying above the concentrate will lead to the formation of a second phase also under precipitation hardening a second phase can also be created via thermal treatments

particle bowing cab be written as :  Δz = Gb / L-2x

iii) work hardening :

Dislocation caused by stress fields been generated hardens metals under the work hardening mechanism

dislocation can be represented as ; Gb √ p

where : G = shear modulus , b = Burgess vector, p = dislocation density

B) The small angle grain boundaries are not effective enough because there is less crystallographic misalignment in the grain boundary region for a small-angle

3 0
3 years ago
If the feedforward path of a control system contains at least one integrating element, then the output continues to change as lo
Thepotemich [5.8K]

Answer:

The attached system shows that there’s an integrator between the point where disturbance enters the system and error measuring element. A any time when R(s)=0 then

\frac {C(s)}{D(s)}=\frac {G(s)}{1+G_c(s)G(s)} and considering that E(s)=D(s)-G_c(s)C(s) then

\frac {E(s)}{D(s)}=1-(\frac {C(s)}{D(s)})G_c(s)

\frac {E(s)}{D(s)}=1-(\frac {G(s)}{1+G_c(s)D(s)})G_c(s)

\frac {E(s)}{D(s)}=\frac {1}{1+G_c(s)G(s)}

E(s)=\frac {D(s)}{1+G_c(s)G(s)}

For ramp disturbance d(t)=at

D(s)=\frac {a}{s^{2}} therefore, the steady state error is given by

e(\infty)= \lim_{s \to 0} s E(s)

e(\infty)= \lim_{s \to 0} s [\frac {D(s)}{1+G_c(s)G(s)}]

e(\infty)= \lim_{s \to 0} s [\frac {a}{s^{2}+s^{2}G_c(s)G(s)}]

e(\infty)= \lim_{s \to 0} s [\frac {a}{s+sG_c(s)G(s)}]

e(\infty)= \lim_{s \to 0} s [\frac {a}{sG_c(s)G(s)}]

Whenever G_c(s) has a double intergrator, the error e(\infty) becomes zero

3 0
3 years ago
The radius of a circle is increased from 5.00 to 5.04 m Estimate the resulting change in area, and then express the estimate as
musickatia [10]

Answer:

1.016%

Explanation:

We need to calculate the rate in the area.

We know that,

A=\pi r^2

A_1=\pi (5)^2 =78.5398m^2\\A_2= \pi(5.04)^2 = 79.8014m^2

The change in area is

A_2-A_1=1.2616m^2

In percentage that represent,

Rate = \frac{A_2}{A_1} = \frac{79.8014}{78.5398} = 1.016\%

3 0
3 years ago
Sally made a diagram to show one way that Earth’s systems interact near a volcano.
ohaa [14]
We won’t be able to do it cuz we can’t draw on this app
5 0
3 years ago
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