3 years ago

Biblical studies of john

Engineering

1 answer:

nevsk [136]3 years ago

5 0

Answer:

<h2>the answer of sols brother is correct</h2><h3>hope it helps you have a good day</h3><h2 />

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Air at T1 = 32°C, p1 = 1 bar, 50% relative humidity enters an insulated chamber operating at steady state with a mass flow rate

RUDIKE [14]

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4.5kg/min

Explanation:

Given parameters

$T_1 = 32^0 C, m_1 = 3 kg/min, T_2 = 7^0 C ,T_3 = 17^0$

if we take

The mass flow rate of the second stream = $m_2(kg/min)$

The mass flow rate of mixed exit stream = $m_3 (kg/min)$

Now from mass conservation

$m_3 = m_2 + m_1$

$m_3 = m_2 + 3 (kg/min)$

The temperature of the mixed exit stream given as

$T_3m_3 = T_2m_2 +T_1m_1\\\\17 ( 3 + m_2) = 7 \times m_2 + 32 \times 3\\\\51 + 17 m_2 = 7 m_2 + 96\\\\10 m_2 = 96 - 51\\\\m_2 = 4.5 kg/min\\\\\\\\$

Therefore the mass flow rate of second stream will be 4.5 kg/min.

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3 years ago

Biblical studies of john​

Biblical studies of john