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malfutka [58]
2 years ago
6

Can someone help me calculate the area of this object?

Mathematics
1 answer:
nekit [7.7K]2 years ago
7 0
Answer: 272.9 cm^2

How to:

25 * 8 = 200

9 * 8.1 = 72.9

Add the areas of the two rectangles

200 + 72.9 = 272.9 cm^2
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What is the value of the expression below when y=8 2y+7
Gala2k [10]

Answer:

23

Step-by-step explanation:

if y=8 then you plug it inti the equation

2(8)+7

16+7=23

3 0
3 years ago
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Solve for x:
Anna71 [15]

Answer:

Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. While factoring may not always be successful, the Quadratic Formula can always find the solution.

The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.

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3 years ago
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The set of all Real numbers between 4 and 7 including 4
erik [133]
4,5,6,7 is your answer
8 0
2 years ago
Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
frez [133]

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

8 0
3 years ago
There is a bag filled with 3 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i
Morgarella [4.7K]

altogether there are 7 marbles in the bag.

put the marbles in fractions, so blue would be 3/7

and red would be 4/7. but becuase you need 2 of the same, you do

3/7 x 3/7 = 9/49

4/7 x 4/7 = 16/49

then add them togther

25/49

if you need it as a percentage, it is

51.020408163265%

8 0
3 years ago
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