3 years ago

I tried answering this many times but i couldn’t get it, can someone please help

Mathematics

1 answer:

azamat3 years ago

6 0

A is the correct answer for your problem.

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At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperature is 50° Celsius. This

dybincka [34]

Answer:

$D(t)=50(0.8)^t$

Step-by-step explanation:

We are given that

Initially the difference between the cake's and the cooler's temperature ,a=50 degree Celsius

$r=\frac{1}{5}/min$

We have to find the function that gives the temperature difference in degrees Celsius D(t).

We know that

$D(t)=a(1-r)^t$

Substitute the values

$D(t)=50(1-\frac{1}{5})^t=50(1-0.2)^t$

$D(t)=50(0.8)^t$

This is required function that gives the temperature difference in degrees Celsius.

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Answer:

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Step-by-step explanation:

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