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Naddika [18.5K]
3 years ago
6

S = R-rR solve for R

Mathematics
2 answers:
-BARSIC- [3]3 years ago
4 0
Look at the attachment

katrin2010 [14]3 years ago
3 0

Answer:

R = -S - rR

Step-by-step explanation:

S = R - rR

R = -S - rR

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Instructions: Create a table of values for the given function.<br> Function: f(x) = -4x + 3
Ahat [919]

Answer:

Domain: {-2, -1, 0, 1, 2}

Range: {-5, -1, 3, 7, 11}

Step-by-step explanation:

Given the function, f(x) = -4x + 3:

We could simply substitute the given x-values into the function to solve for its corresponding y-values:

x = -2:

f(-2) = -4(-2) + 3

f(-2) = 8 + 3

f(-2) = 11

x = -1:

f(-1) = -4(-1) + 3

f(-1) = 4 + 3

f(-1) = 7

x = 0:

f(0) = -4(0) + 3

f(0) = 0 + 3

f(0) = 3

x = 1:

f( 1 ) = -4( 1 ) + 3

f( 1 ) = -4 + 3

f( 1 ) = -1

x = 2:

f(2) = -4(2) + 3

f(2) = -8 + 3

f(2) = -5

Attached is a screenshot of the table containing the same solution displayed in this post.

6 0
3 years ago
Please help, it's urgent!
Aneli [31]

For this case we have to, by defining properties of powers and roots the following is fulfilled:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

We must rewrite the following expression:

\sqrt [3] {8 ^ {\frac {1} {4} x}}

Applying the property listed we have:

\sqrt [3] {8 ^ {\frac {1} {4} x}} = 8 ^ {\frac{\frac {1} {4} x} {3} }= 8 ^ {\frac {1} {4 * 3} x} = 8 ^ {\frac {1} {12} x}

Using the property again we have to:

8 ^ {\frac {1} {12} x} = \sqrt [12] {8 ^ x}

Thus, the correct option is option C

Answer:

Option C

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4 years ago
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What is 2.32 writin in fraction form
zimovet [89]
2.32= \frac{2.32\times 100}{1\times 100} = \frac{232}{100} =2 \frac{32}{100} =\boxed {2 \frac{8}{25} }
4 0
4 years ago
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Graph y&lt; -2/3x +6<br><br> Please help ASAP
Fed [463]
Your answer would be the one on the bottom left. I recommend the app “Mathaway” that will help you graph problems like this.
4 0
4 years ago
The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that the temperature is c
Valentin [98]

Answer:

idk this is actually hard

Step-by-step explanation:

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