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2 years ago

Factor x^2-a^2-10a-25 completely.

Mathematics

1 answer:

PtichkaEL [24]2 years ago

5 0

Answer:

(x-a-5)(x+a+5)

Step-by-step explanation:

x^2-(a^2+10a+25)

x^2-(a+5)^2

(x-(a+5))×(x+(a+5)

(x-a-5)×(x+a+5)

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\large -6x+6y=6<br> \large 6x+3y=12

Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1) = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0

3 years ago

Help plz!!!!!!!!

VashaNatasha [74]

A(1.3) (3,1) idk if it’s right but seems like the right answer

5 0

3 years ago

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

Harman [31]

Formula for the perimeter of a quarter circle: C = ((pi x 2r) / 4) + 2r

C = ((3.14 x 18) / 4) + 18

C = (56.52 / 4) + 18

C = 14.13 + 18

C = 32.13 miles

Hope this helps! :)

5 0

3 years ago

If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI

Vikentia [17]

Answer:

The value is $y = \$ 225$

Step-by-step explanation:

From the question we are told that

The amount charge per year is $k = \$ 200$

The number of members it will have at this amount is $n = 50$

The amount amount increase that will lead to the loss of a single member is $z = \$ 5$

Generally the total amount the club would obtain from its members is mathematically represented as

$I = Amount \ due\ paid * Number \ of members$

Now let x denote the number of member lost

Hence

$I = (k + zx) (n-x )$

=> $I = (200 + 5x) (50-x )$

=> $I = 10000+50x-5x^2$

Thus the number of members that be removed to give the maximum income from dues is obtained by differentiating the above equation and equating it to zero

$\frac{dI}{dx} = 50-10x$

=> $x = 5$

So from $I = (200 + 5x) (50-x )$ we have

$I = (200 + 5 (5)) (50-5 )$

$I = \$ 10125$

So the amount the club should charge is

$y = \frac{10125}{50 - 5}$

$y = \$ 225$

7 0

3 years ago

Tristan has 45 apples and 20 pears that he is putting into gift baskets. Each basket will have the same number of apples and pea

const2013 [10]

i think 7 but i am not very sure

7 0

3 years ago