Question

Given: (DE) is a midsegment of ∆ABC. Show all work.

Answer 1

Answer:

Step-by-step explanation:

As they are similar triangles

24/AB = 24/2AD = 12/AD = (x + 2)/AD

12 = x + 2

x = 10

(y + 6) + (x - 3) / 24 = (y + 6)/(x + 2)

(y + 6) + (10 - 3) / 24 = (y + 6)/(10 + 2)

             (y + 13) / 24 = (y + 6)/12

                 12(y + 13) = 24(y + 6)

                12y + 156 = 24y + 144

                          12y = 12

                             y = 1

AC = (y + 6) + (x - 3)

AC = (1 + 6) + (10 - 3)

AC = 14