All categories

3 years ago

What is 9x-4x+-5x ????????????????????????

Mathematics

1 answer:

Murrr4er [49]3 years ago

7 0

9x-4x+-5x=0 because 9x-4x is 5x and 5x+-5x is 0

You might be interested in

What’s the answer pls

larisa [96]

Amount of interest = 3/100 x 1200
= $36

Answer is B

3 0

3 years ago

I need help on this number sequence

MrRa [10]

You would square 3968 and subtract 1.

5 0

3 years ago

Read 2 more answers

A number divided by 6 minus -3 equals 12

liberstina [14]

Let the number be x.

Therefore, by the problem

x/6-(-3) = 12

or, x/6+3 = 12

or, x/6 = 12-3

or, x/6 = 9

or, x = 9 × 6

or, x = 54

The number is 54.

4 0

2 years ago

Read 2 more answers

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

Plz help fast!

sdas [7]

A scatter plot matrix shows all pairwise scatter plots for many variables. If the variables tend to increase and decrease together, the association is positive. If one variable tends to increase as the other decreases, the association is negative, I hope this helps

8 0

2 years ago