Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
14= 4 pi/6 pi = 2/3
15 = 8 pi/10 pi = 4/5
16 = no
I believe that the answeres are either (The functions have the same shape. The Y intercept of y= |x| is 0, and the y-intercept of the second function is -9) or ( the two functions are the same) my best guess is (The functions have the same shape. The Y intercept of y= |x| is 0, and the y-intercept of the second function is -9)
Find the angle between lines; 0.5880 rad, 33.7°
Answer: 0.5880 rad. 33.7°
Answer:
there's no graph??
Step-by-step explanation:
