Answer:
An equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
Step-by-step explanation:
The given expression is:
x2-16x+12
Break the constant term:
x^2-16x-36 +48=0
[x^2-16x-36] +48=0
Now break the middle term inside the brackets
(x^2-18x+2x-36)+48=0
Take the common
[x(x-18) +2(x-18)]+48=0
(x-18)(x+2)+48=0
Thus an equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
Answer:
B i would be good i solve 20 minutes
Answer:
c. -13/4.
d. -13/3.
Step-by-step explanation:
c. f(3/2) = (1/2)(3/2) - 4
= 3 / 4 - 4
= 0.75 - 4
= -3.25
= -3 and 1/4
= -13/4.
d. f(-2/3) = (1/2)(-2/3) - 4
= -2/6 - 4
= -1/3 - 4
= -1/3 - 12/3
= -13/3.
Hope this helps!
2 in 83628 is the tenths and 208 is the hundreds
Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q