Diameter = 2*radius
14/2=7
Radius is 7in"
Circumference of circle formula: 2pi(radius)
2pi(7)= 43.98in of wire required so it can wrap around lamp exactly once.
Answer:
Part A: x0.50 + 3 = 18.50
Part B: x0.75 + 3 - x0.10 = 21
Part C: The equations from Part A and Part B differ because of the cost of plastic cup.
Step-by-step explanation:
Let x represent the number of cup of lemonade sold. Therefore, we have:
Part A:
This situation can be represented by the following equation:
x0.50 + 3 = 18.50
Part B:
This situation can be represented by the following equation:
x0.75 + 3 - x0.10 = 21
Part C:
The equations from Part A and Part B differ because of the cost of plastic cup.
For equation from Part A, revenue is the same as profit as Sydney does incur any cost to buy plastic cup before selling her lemonade.
For equation from Part B, revenue is different from profit because Daria has to incur the cost of plastic cup which $0.10 per cup of lemonade before selling her lemonade.
Answer:
(2. 16/24) (3. 0 (because there are no green shirts))
Step-by-step explanation:
Hope it helps!
Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
Answer:
The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.
Step-by-step explanation:
The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.
We have to find the roots of this given equation.
If a quadratic equation is of the form 
Its roots are 
and 
Here the given equation is 
= 0
a = 2
b = -4
c = -1
If the roots are 
, then
= 
= 
= 
= 
= 
= 
These are the two roots of the equation.
