Under his cell phone plan, Nathaniel pays a flat cost of $41 per month and $4 per gigabyte. He wants to keep his bill at $45.80
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Calling x and y the two sizes of the rectangular field, the problem consists in finding the minimum values of x and y that give an area of 
.
The area is the product between the two sizes:
(1)
While the perimeter is twice the sum of the two sizes:
(2)
From (1) we can write
and we can substitute it into (2):
To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:
The derivative of the perimeter is
If we require p'(x)=0, we find
And the other side is
This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.
The area is the product between the two sizes:
While the perimeter is twice the sum of the two sizes:
From (1) we can write
and we can substitute it into (2):
To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:
The derivative of the perimeter is
If we require p'(x)=0, we find
And the other side is
This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.
You have to find the difference between 4 1/2 and 1 7/8, in other words subtract those. MAKE SURE YOU SUBTRACT 4 1/2 MINUS 1 7/8, IF YOU DO IT THE OTHER WAY AROUND, IT WILL IMPACT YOUR ANSWER.
In order to subtract correctly, you have to make them common denominators.
CORRECT ANSWER- B= 2 5/8
