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Butoxors [25]
2 years ago
10

It takes violet 3/5 hour to paint a chair. How much of the chair will be finished after 1/3 hour? Plz answer this plzzzzz!!

Mathematics
1 answer:
Anon25 [30]2 years ago
5 0
The anwser is c your welcome
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Can someone plz help me as soon as possible plz someone help me ASAP
Ghella [55]

Answer:

4 pages per hour

Step-by-step explanation:

We want to find the pages per hour

Take the pages and divide by the hours

7

-----

1 3/4

Change to an improper fraction

7

-----

7/4

Multiply the top and bottom by 4/7

7*4/7

-----

7/4 *4/7

4

-----

1

He can write 4 pages per hour

4 0
3 years ago
The distance traveled varies directly with the time spent in motion when speed is held constant. If d represents the distance tr
Artist 52 [7]

Answer:

Constant K = 38

Time t = 5.3

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP!! DESPERATE
9966 [12]

a) i) Since blood types across individuals are independent, we have

Pr[1 = A and 2 = B] = Pr[1 = A] • Pr[2 = B]

where e.g. Pr[1 = A] means "probability that partner 1 has type A blood". According to the given distribution,

Pr[1 = A and 2 = B] = 0.37 • 0.13 = 0.0481 = 4.81%

a) ii) The event that partner 1 has type A and partner 2 has type B is exclusive from the event that partner 1 has type B and partner 2 has type A, and vice versa. In other words, only one of these events can happen, and not both simultaneously. This means the probability of either event occurring is equal to the sum of the probabilities of these events occurring individually. Then

Pr[(1 = A and 2 = B) or (1 = B and 2 = A)]

= Pr[1 = A and 2 = B] + Pr[1 = B and 2 = A]

Both probabilities are the same, and we found it in the previous part. So

Pr[(1 = A and 2 = B) or (1 = B and 2 = A)]

= 0.0481 + 0.0481 = 0.0962 = 9.62%

a) iii) The event that at least one partner has type O occurs if exactly one partner has type O, or both do. That is, "at least one partner with type O" contains 3 possible events,

• 1 = O and 2 = not O

• 1 = not O and 2 = O

• 1 = O and 2 = O

For the first event, by independence, is

Pr[1 = O and 2 = not O] = Pr[1 = O] • Pr[2 = not O]

and by definition of complementary event,

Pr[1 = O and 2 = not O] = Pr[1 = O] • (1 - Pr[2 = O])

From the given distribution, it follows that

Pr[1 = O and 2 = not O] = 0.44 • (1 - 0.44) = 0.2464 = 24.64%

The second event is the same as the first in terms of probability.

For the third event, we have

Pr[1 = O and 2 = O] = Pr[1 = O] • Pr[2 = O] = 0.44² = 0.1936 = 19.36%

Then the total probability of at least one O-type partner is

24.64% + 24.64% + 19.36% = 68.64%

b) Suppose partner 1 is type-B. Then partner 2 is an acceptable donor if they are either type-B or type-O. So we want to find

Pr[1 = O and (2 = B or 2 = O)]

By independence,

= Pr[1 = O] • Pr[2 = B or 2 = O]

By mutual exclusivity,

= Pr[1 = O] • (Pr[2 = B] + Pr[2 = O])

Then from the given distribution,

= 0.44 • (0.13 + 0.44) = 0.2508 = 25.08%

Now suppose partner 2 is type-B. Then partner 1 must be either type-B or type-O. But the math works out the same way, so that the overall probability is

25.08% + 25.08% = 50.16%

7 0
2 years ago
You have a rectangular piece of cardboard that is 6 feet long and 5 feet wide. You want to make a box, so you cut out squares
Wewaii [24]

Answer:

(6-2x)(5-2x)(x)=10

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x -----> the edges of the squares in feet

we know that

The volume of the box is equal to

V=LWH

we have

L=(6-2x)\ ft\\W=(5-2x)\ ft\\H=x\ ft

V=10\ ft^3

substitute and solve for x

10=(6-2x)(5-2x)(x)\\10=(30-12x-10x+4x^{2})(x)\\10=(30x-22x^2+4x^{3})\\4x^{3}-22x^{2} +30x-10=0

therefore

The equation that you would use to solve for x is

(6-2x)(5-2x)(x)=10

5 0
3 years ago
Mr ramos invest $500 at a simple interest rate of 6%. How much interest will he earn in one year
Alenkasestr [34]

Answer

=30

Step-by-step explanation:

principal*rate*time

Principal:$500

Rate:6% =6/100

Time:1 year

$500*6/100*1=

$30

3 0
3 years ago
Read 2 more answers
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