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NeTakaya
3 years ago
11

Type a digit that makes this statement true. 40,338,74 is divisible by 8.

Mathematics
2 answers:
Basile [38]3 years ago
7 0

Answer:

4

Step-by-step explanation:

40,338,744 / 8 = 5042343

loris [4]3 years ago
7 0
What is divisible by 8 4 and 2
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HELPPPPPPP PLEASEEEEE
egoroff_w [7]

Answer:

5^15

Step-by-step explanation:

if they have the same base then you add the two top vaules therfore giving you c.

Brainliest plzzzzzzz

4 0
3 years ago
Find the equation of the line.<br> Use exact numbers.
Marina CMI [18]

Answer:

Y=3x+3

The y intercept is 3 and use rise over run to find m.

8 0
3 years ago
If a man take one and a half mins to paint a door how much doors can he paint in seven half hour
sashaice [31]

Answer:

300 doors.

Step-by-step explanation:

1.5 minutes for 1 door.

7.5 hours for 300 doors.

7.5 hours = 450 minutes.

\frac{450}{1.5}=300

7 0
3 years ago
(1) (10 points) Find the characteristic polynomial of A (2) (5 points) Find all eigenvalues of A. You are allowed to use your ca
Yuri [45]

Answer:

Step-by-step explanation:

Since this question is lacking the matrix A, we will solve the question with the matrix

\left[\begin{matrix}4 & -2 \\ 1 & 1 \end{matrix}\right]

so we can illustrate how to solve the problem step by step.

a) The characteristic polynomial is defined by the equation det(A-\lambdaI)=0 where I is the identity matrix of appropiate size and lambda is a variable to be solved. In our case,

\left|\left[\begin{matrix}4-\lamda & -2 \\ 1 & 1-\lambda \end{matrix}\right]\right|= 0 = (4-\lambda)(1-\lambda)+2 = \lambda^2-5\lambda+4+2 = \lambda^2-5\lambda+6

So the characteristic polynomial is \lambda^2-5\lambda+6=0.

b) The eigenvalues of the matrix are the roots of the characteristic polynomial. Note that

\lambda^2-5\lambda+6=(\lambda-3)(\lambda-2) =0

So \lambda=3, \lambda=2

c) To find the bases of each eigenspace, we replace the value of lambda and solve the homogeneus system(equalized to zero) of the resultant matrix. We will illustrate the process with one eigen value and the other one is left as an exercise.

If \lambda=3 we get the following matrix

\left[\begin{matrix}1 & -2 \\ 1 & -2 \end{matrix}\right].

Since both rows are equal, we have the equation

x-2y=0. Thus x=2y. In this case, we get to choose y freely, so let's take y=1. Then x=2. So, the eigenvector that is a base for the eigenspace associated to the eigenvalue 3 is the vector (2,1)

For the case \lambda=2, using the same process, we get the vector (1,1).

d) By definition, to diagonalize a matrix A is to find a diagonal matrix D and a matrix P such that A=PDP^{-1}. We can construct matrix D and P by choosing the eigenvalues as the diagonal of matrix D. So, if we pick the eigen value 3 in the first column of D, we must put the correspondent eigenvector (2,1) in the first column of P. In this case, the matrices that we get are

P=\left[\begin{matrix}2&1 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}3&0 \\ 0 & 2 \end{matrix}\right]

This matrices are not unique, since they depend on the order in which we arrange the eigenvalues in the matrix D. Another pair or matrices that diagonalize A is

P=\left[\begin{matrix}1&2 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}2&0 \\ 0 & 3 \end{matrix}\right]

which is obtained by interchanging the eigenvalues on the diagonal and their respective eigenvectors

4 0
3 years ago
X =<br>Angle measure <br>in the following picture solve for x ​
rjkz [21]

Answer:

x=11

Step-by-step explanation:

3x+28+5x+52+12=180

8x+92=180

-92 on both sides

8x=88

/8 on both sides

x=11

8 0
3 years ago
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