Ask question

Ask question

All categories

3 years ago

8

suppose that a cell phone plan charges $15 for the first 60 minutes or less used in a month and $0.50 for each additional minute

. Write a piecewise function that shows the charges for time t where t ranges from 0 to 63 minutes

1 answer:

cupoosta [38]3 years ago

8 0

F(x)=15 when x<span>≤60
=.5(x-60)+15 when x>60
</span>

You might be interested in

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

4 years ago

Carrie's friend lives two miles from her house. If it took her 18 % minutes to run to heltriend's

agasfer [191]

Answer: 1.75hours or 1.45

Step-by-step explanation:

8 0

3 years ago

A computer downloads files at a constant rate. The table shows how many megabytes the computer downloads over specific lengths o

PolarNik [594]

The slope of the line would be 3.75.

5 0

3 years ago

Write a number between 0 to 20 that has two factors

Angelina_Jolie [31]

4
6

Cause 4 times 1 and 2 times 2

5 0

3 years ago

Read 2 more answers

There are 35 students in art class and 57 students in dance class. Find the number of students who are either in art class or in

Murrr4er [49]

Answer:

a. 80 students

b. 92 students

Step-by-step explanation:

Represent arts students with A and Dance students with D.

So, we have,

n(A) = 35

n(D) = 57

Required

Determine n(A or D)

Solving (a):

Here, we have:

n(A and D) = 12

n(A or D) is calculated as thus:

n(A or D) = n(A) + n(D) - n(A and D)

n(A or D) = 35 + 57 - 12

n(A or D) = 80

b. From the given details

n(A and D) = 0 because both students are not mixed up as in (a) above

Using the same formula as (a).

n(A or D) = n(A) + n(D) - n(A and D)

n(A or D) = 35 + 57 - 0

n(A or D) = 92

8 0

3 years ago