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sineoko [7]
2 years ago
10

Officer Brimberry wrote 32 tickets for traffic violations last week, but only 12 tickets this week. What is the percent decrease

? Give your answer to the nearest tenth of a percent. [The percent decrease is___%​
Mathematics
1 answer:
kolbaska11 [484]2 years ago
4 0

Answer:

62.5 %

Step-by-step explanation:

you have to subtract 32-12, which equals 20

then divide 20 by the original amount (20/32)

20/32= .625, then you have to multiply to get the final answer...hope this helped!

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(10. 2x+16=5x-17 find qs<br>​
mylen [45]

Answer:

x = 11

Step-by-step explanation:

2x + 16 = 5x - 17

     + 17         + 17

2x + 33 = 5x

- 2x          - 2x

      33 + 3x

33/3 = 11

3x/3 = x

4 0
3 years ago
A food chemist salary is between 50000 to 100000 what is the median salary of this job
Verizon [17]
50,000 + 100,000 = 150,000

Divide 150,000/2 and it equals 75,000
5 0
3 years ago
Micheal cuts grass for $15.00 per lawn. He cuts 2 lawns each day for 6 days a week. How much will Micheal earn in 2 weeks?
jek_recluse [69]
*First you want to find out how much he makes a day
15x2=30
*so for 2 weeks he made $30 a day 
*Obliviously there are 7 days a week so 7x2=14
*Now multiply 14x30= $420 
hope I helped!
3 0
3 years ago
Read 2 more answers
Estimate each product 3/4 times 23
storchak [24]
We would have to convert 3/4 to a decimal of 0.75 (the equivalent)
0.75*23 = 17.3

-or-

3 * 23 = 69
4 * 23 = 92
6 0
3 years ago
You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o
anyanavicka [17]

Answer:

x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

=\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0

-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0

\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}

squaring both sides; we get

\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}

\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}

By cross multiplying; we get

49x^2 = 25(54^2+x^2)

49x^2 = 25 \times 54^2+ 25x^2

49x^2-25x^2 = 25 \times 54^2

24x^2 = 25 \times 54^2

x^2 = \dfrac{25 \times 54^2}{24}

x =\sqrt{ \dfrac{25 \times 54^2}{24}}

x =\dfrac{5 \times 54}{\sqrt{24}}

x =\dfrac{270}{\sqrt{4 \times 6}}

x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}

x =\dfrac{45 \sqrt{6}}{ 2}

8 0
3 years ago
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