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2 years ago

Decide whether n = 9 is a solution to the equation 2+n=7. Write yes or no

Mathematics

1 answer:

mel-nik [20]2 years ago

3 0

Answer:

No. The answer would be n=5

Step-by-step explanation:

You have to subtract the 2 from both sides to cancel it out on the left side. so you would be doing 7-2, not 7+2

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PLEASE HELP ANSWER BOTH PARTS!!! DUE SOON

soldi70 [24.7K]

Answer:

c. 69

b. 7

Step-by-step explanation:

4 0

1 year ago

A two-factor between-subjects design is evaluated. The F-value for Factor A has df = 1, 40 and the F-value for Factor B has df =

finlep [7]

Answer:

The df values for the A x B interaction are also 3,40

Step-by-step explanation:

The F-value for Factor A has df = 1, 40

The F-value for Factor B has df = 3, 40.

The df values for the A x B interaction are also 3,40

This is because the source of variation between columns has ( c- 1); rc(n-1) degrees of freedom and the source of variation between rows has (r-1); rc(n-1) degrees of freedom and the source of variation of interaction

(between rows and columns) has ( c-1) ( r-1); rc(n-1) degrees of freedom.

Therefore

Factor A: ( c- 1); rc(n-1) = 1,40

<u>Factor B: (r-1); rc(n-1) = 3,40</u>

Interaction : ( c-1) ( r-1); rc(n-1) = 3*1,(40)= 3,40

where c refers to columns , r refers to rows and n refers to the total sample size.

5 0

2 years ago

2b^2 +32b + 128 <br> Pls answer this

KengaRu [80]

Answer:

${2b}^{2} + 32b + 128$

Factor and get

$x = - 8$

8 0

3 years ago

Read 2 more answers

Colleen recorded the type of trees in the woods near her house. She counted 20 spruce trees and 50 maple trees. What is the expe

tankabanditka [31]

Answer:

The answer is A $\frac{2}{7}$

Step-by-step explanation:

3 0

3 years ago

Solve the following system of equations. What is one x-value of a solution?

gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

$x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}$

$x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}$

$x = \frac{-36 \pm 33.11}{2}$

$x_1 = \frac{-36 + 33.11}{2}$

$x_1 = -1.445$

$x_2 = \frac{-36 - 33.11}{2}$

$x_2 = -34.555$

5 0

3 years ago