Can you show the original problem? It seems good to me, but seeing the original could help.
Answer:
24
Step-by-step explanation:
I think it’s right
To solve the give logarithm we proceed as follows;
log7(3x^3+x)-log7(x)=2
this can be written as:
log7[(3x^3+x)/(x)]=2
but;
log7(49)=2
thus;
log7(3x^3+x)/x=log7(49)
hence canceling log7 we get:
(3x^3+x)/x=49
This can be simplified further to get:
3x^2+1=49
3x^2=49-1
3x^2=48
x^2=48/3
x^2=16
getting the square root of both sides we get:
x=4
the answer is x=4
Answer:
A
Step-by-step explanation:
Just plug in 
.
(6x^3-2x^2+4) <span>- (2x^3+4x^2-5)
Subtract the like terms
6x^3 - 2x^3 = 4x^3
-2x^2 - 4x^2 = -6x^2
4 - (-5) = 9
The final answer would be
4x^3 - 6x^2 + 9
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