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labwork [276]
2 years ago
11

The value of x² – 2yx + y² when x = 1, y = 2 is

Mathematics
2 answers:
Mrrafil [7]2 years ago
7 0
7
The process
1-2(2x1)+(2)^2
ki77a [65]2 years ago
5 0

x^2 - 2xy +y^2 = (x-y)^2 = (1-2)^2 = (-1)^2 =1

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In the year 2005, there were 100 rabbits in a particular region. Since then, the population has increased by 3.4% per year. Writ
Andreas93 [3]

Answer:

Step-by-step explanation:

Your answer

Ok, lets do it systematically.

2005– 100 rabbits

3.4 % per year increasement.

So every year it increase 0.034 *100 = 3.4 per year

Total 2025-2005= 20 years

So expression is : 0.034*100*year(20)

Answer is : 3.4*20 = 68. So, in 2025, total rabbits will be 168

Mark it as Brainlist answer. Follow me.

3 0
3 years ago
A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
3 years ago
A car is traveling at a speed of 75 km/h. Compute the speed of the car in m/s.
Nonamiya [84]
46.603 mph. or 47 mph rounded.
3 0
3 years ago
Read 2 more answers
Can someone help me with this problem. I don’t know how to do volume.
densk [106]

Answer:

7.5in³

Step-by-step explanation:

1x5x1.5=7.5

7 0
3 years ago
What is 528 1/5 - 89 3/5
sergiy2304 [10]
The answer is 438.6...
(528+1/5)-(89+3/5)=438.6
8 0
3 years ago
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