*see attachment for the diagram
Answer:
A. 178 units²
Step-by-step explanation:
Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)
✔️Surface area of the square pyramid = s² + 2*s*l
Where,
s = side length of square base (w) = 6 units
l = slant height = ?
Use Pythagorean theorem to find l
l = √((w/2)² + y²)
l = √((6/2)² + 5²) = √(9 + 25)
l = √34
l ≈ 5.8 units
Surface area of the square pyramid = 6² + 2*6*5.8 = 105.6 units²
✔️Surface area of square prism:
SA = 2a² + 4ah
Where,
a = w = 6 units
h = x = 3 units
Substitute
SA = 2(6²) + 4*6*3
= 72 + 72
= 144 units²
✔️base area of the square pyramid = s²
s = w
Base area = 6²
Base area = 36 units²
✅Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)
Surface area of the figure = (105.6 + 144) - 2(36)
= 249.6 - 72
= 177.6
≈ 178 units²
We know that in order to find the point (-3,-7), we must first go to the left on the x-axis 3 units from the origin, and then directly down on the y-axis 7 units. Using the attached image, we can see that this would then put us into the third quadrant or Quadrant III. Therefore, the answer is D) The point is in the third quadrant.
If Sin 60 = √3 / 2
Then, Cos 60 = ?
Well, we know :
Sin^2x + Cos^2x = 1
Let X = 60°
That is,
Sin^2(60) + Cos^2(60) = 1
(√3 / 2)^2 + Cos^2(60) = 1
3 / 4 + Cos^2(60) = 1
Cos^2(60) = 1 - 3/4
Cos^2(60) = 4/4 - 3/4
Cos^2(60) = (4-3)/4
Cos^2(60) = 1/4
Cos(60) = √(1/4)
Cos(60) = √1 / √4
Cos(60) = 1 / 2
This's answer right to the your question.
Answer:
565.2
Step-by-step explanation:
Cone=1/3bh
B is pir^2
so that means b=pi36 (6*6 =36)
36*15/3 is 565.2