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tensa zangetsu [6.8K]
3 years ago
15

Solve In standard form y+1=2/3(×+4)

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0
Standard form is another way of saying slope-intercept form. The equation you have there is in point-slope form, so we must convert this to slope-intercept form to get our final answer.

In point-slope form (y - k = m(x - h)) k is the y-value, h is the x-value, and m is the slope. All we must do is change your equation's form into standard form, or slope-intercept form which looks like this: (y = mx + b), where m is the slope and b is the y-intercept.

Convert this equation y + 1 = 2/3(x + 4) into standard/slope-intercept form.
y + 1 = 2/3(x + 4)
y + 1 = 2/3x + 2.666 Here we multiplied 2/3 by x and 4 since x + 4 is in parenthesis next to 2/3.
y + 1 - 1 = 2/3x + 2 2/3 - 1 Now we want to get y by itself so the form will look like y = mx + b, so we subtract the 1 from both sides of the equation. (2 2/3 is a mixed fraction that is equal to 2/3*4.)
y = 2/3x + 1 2/3

This is our final answer since it is in the standard, or slope-intercept form. Hope this made sense! If you have any questions please ask.
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The mean per capita income is 23,037 dollars per annum with a variance of 149,769. What is the probability that the sample mean
mihalych1998 [28]

Answer:

Probability that the sample mean would be less than 23,013 dollars is 0.2358.

Step-by-step explanation:

We are given that the mean per capita income is 23,037 dollars per annum with a variance of 149,769.

Also, a sample of 134 persons is randomly selected.

Firstly, Let \bar X = sample mean

The z-score probability distribution for sample mean is given by;

              Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean per capita income = 23,037 dollars p.a.

           \sigma = standard deviation = \sqrt{Variance} = \sqrt{149,769} = 387 dollars p.a

           n = sample of persons = 134

So, probability that the sample mean would be less than 23,013 dollars is given by = P(\bar X < 23,013 dollars)

      P(\bar X < 23,013) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{23,013-23,037}{\frac{387}{\sqrt{134} } } ) = P(Z < -0.72) = 1 - P(Z \leq 0.72)

                                                                    = 1 - 0.7642 = 0.2358

The above probability is calculated using the z-score table.

<em>Therefore, probability that the sample mean would be less than 23013 dollars if a sample of 134 persons is randomly selected is 0.2358.</em>

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Natali [406]

Hi!

6*7-27*9+64

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