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tensa zangetsu [6.8K]
3 years ago
15

Solve In standard form y+1=2/3(×+4)

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0
Standard form is another way of saying slope-intercept form. The equation you have there is in point-slope form, so we must convert this to slope-intercept form to get our final answer.

In point-slope form (y - k = m(x - h)) k is the y-value, h is the x-value, and m is the slope. All we must do is change your equation's form into standard form, or slope-intercept form which looks like this: (y = mx + b), where m is the slope and b is the y-intercept.

Convert this equation y + 1 = 2/3(x + 4) into standard/slope-intercept form.
y + 1 = 2/3(x + 4)
y + 1 = 2/3x + 2.666 Here we multiplied 2/3 by x and 4 since x + 4 is in parenthesis next to 2/3.
y + 1 - 1 = 2/3x + 2 2/3 - 1 Now we want to get y by itself so the form will look like y = mx + b, so we subtract the 1 from both sides of the equation. (2 2/3 is a mixed fraction that is equal to 2/3*4.)
y = 2/3x + 1 2/3

This is our final answer since it is in the standard, or slope-intercept form. Hope this made sense! If you have any questions please ask.
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One button is kept a -3 in which direction and how many steps should we move to reach at -9?

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Answer:

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Step-by-step explanation:

The Median of the data 78,56,22,34,45,54,39,68,54,84

Median of a data is the value at the middle after rearrangement

Rearrange in ascending 0rder

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The two numbers at the middle are 54 and 54

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Hence the median of the data is 54

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1 year ago
Consider a queueing system with one server and infinite capacity. Suppose the arrival rate at the queue is 36 customers per hour
Virty [35]

Answer:

a) The average waiting time before the customer begins service is 13.5 minutes.

b) Number of customers are waiting to be served is 8.1.

Step-by-step explanation:

Given : Consider a queuing system with one server and infinite capacity. Suppose the arrival rate at the queue is 36 customers per hour, there are 9 customers on average in the system at any given time, and a server can serve 40 customers per hour.

To find :

a) What is the average waiting time before the customer begins service (in minutes)?

b) On average, how many customers are waiting to be served?

Solution :

A queueing system with one server and infinite capacity.

Let \lambda be the arrival rate of customers i.e.  \lambda=36/hr

L be the average number of customers in the system i.e. L=9

\mu be the number of customers a server can serve i.e. \mu=40/hr

Average utilization of system is given by,

P=\frac{\lambda}{\mu}

P=\frac{36}{40}

P=\frac{9}{10}

P=0.9

Average time spent waiting in the system is given by,

W=\frac{1}{\mu-\lambda}

W=\frac{1}{40-36}

W=\frac{1}{4}

W=0.25

a) The average waiting time before the customer begins service is given by,

A_w=P\times W

A_w=0.9\times 0.25

A_w=0.225\ hr

Converting into minutes,

1 hour = 60 minutes

0.225 hour = 0.225\times 60 minute

0.225 hour = 13.5 minute

The average waiting time before the customer begins service is 13.5 minutes.

b) Number of customers are waiting to be served is given by,

n=P\times L

n=0.9\times 9

n=8.1

Number of customers are waiting to be served is 8.1.

3 0
3 years ago
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