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almond37 [142]
2 years ago
13

3,415.72 - 1,838.28 = 1577.44

Mathematics
1 answer:
n200080 [17]2 years ago
4 0
$911.25.

6.25x24.3= 151.875
151.875x6=911.25
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Salsk061 [2.6K]

Answer:

{290,315,340, 365, 390, 415, 440, 465} That's the answer. Its hard for me to explain how i got it.

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One leg of a right triangle measures 6 inches. The remaining leg measures 6 sq 3 inches. What is the measure of the angle opposi
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“6 sq 3 inches “ ? Explain it briefly I’m trying to understand
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3 years ago
When two six-sided dice are rolled what is the probability that the product of their scores will be greater than six?
Pachacha [2.7K]

Answer:   \bold{\dfrac{11}{18}}

<u>Step-by-step explanation:</u>

Think of the products row by row:

11  12  13  14  15  16  - 0 products greater than 6

21 22 23 24 25 26  - 3 products greater than 6

31 32 33 34 35 36  - 4 products greater than 6

41 42 43 44 45 46   - 5 products greater than 6

51 52 53 54 55 56  - 5 products greater than 6

61 62 63 64 65 66  - 5 products greater than 6

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8 0
3 years ago
Read 2 more answers
Write 3x 1/2 in radical form
stiv31 [10]

Answer:

3x^1/2 in radical form is

\sqrt{3x}

Hope this helps you

8 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

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Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
3 years ago
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