HELP ASAP!!! 2nd time I had to ask this!! Pls give the real answer.
1 answer:
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The common ratio in a geometric sequence is the ratio between 2 consecutive terms:
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let
be the nth term of the sequence, then
.
.
.
so clearly
and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let
.
.
.
so clearly
and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>
Answer:
75.44 Square Inches
Step-by-step explanation:
The diagram of the problem is produced and attached.
To determine the area of the cleaned sector:
Let the radius of the larger sector be R
Let the radius of the smaller sector be r
Area of the larger sector
Area of the smaller sector
Area of shaded part =Area of the larger sector-Area of the smaller sector
From the diagram, R=10 Inch, r=10-7=3 Inch,
Therefore, Area of the sector cleaned
