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Alexandra [31]
2 years ago
5

I need help with math algebra

Mathematics
2 answers:
miv72 [106K]2 years ago
8 0
What question would you like help with? I’ll be happy to assist you.
Nutka1998 [239]2 years ago
3 0
What is the question you need help with?
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PLEASE HELP GEOMETRY QUESTION
tino4ka555 [31]

Answer:

Step-by-step explanation:

8 0
2 years ago
He fastest that a seahorse can travel is 2,640 feet per hour. What is its top speed in miles per hour?
Slav-nsk [51]

Answer:

Step-by-step explanation:

You get 2640 and double it which is 5280 and then do 2640/5280 which is 0.5, that is the amount of miles in 2640 feet. So the answer is 0.5 mph which is C

6 0
2 years ago
A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a​ single-strand electric
otez555 [7]

Answer:

dimension are 350 m and 350 m  and

area is 122500 m²

Step-by-step explanation:

Given data

perimeter is 700 m

to find out

the largest area and its​ dimensions

solution

we consider x and y are the sides

so area is xy

perimeter is 2x+ y = 700

so we can say y = 700 -2x

so area will be = x (700 - 2x)

area = 700x - 2x²

we take derivative here and equal to zero

dA/dt = 700x - 2x²

700 - 4x = 0

x = 700/4

x = 175

so will be

y = 700 -2x

y = 700 -2(175)

y = 350

so dimension are 350 m and 350m

area is 122500 m²

3 0
2 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
2 years ago
A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯
ivanzaharov [21]

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = \frac{\text{Dimension of the image}}{\text{Dimension of the original}}

2 = \frac{P'Q'}{PQ}

2 = \frac{P'Q'}{2}

P'Q' = 4 cm

Similarly, for the length of A'B',

2 = \frac{A'B'}{AB}

2 = \frac{A'B'}{1.5}

A'B' = 3 cm

For the length of M'N',

2 = \frac{M'N'}{MN}

2 = \frac{M'N'}{3}

M'N' = 6 cm

4 0
2 years ago
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