Question

What is the equation of a line with a slope of 7 and a point (1, 8) on the line? Express the equation in the form of ​ y=mx b ​ , where m is the slope and b is the y-intercept. Enter your answer in the box.

Answer 1

The equation of a line is $y = 7x+1$.

Given that,

The slope of the line is 7 and a point (1, 8) on the line.

We have to find,

The equation of the line is in the form of $\rm y = mx +c$.

According to the question,

The standard form of the equation having slope m and y in the intercept can be written as,

$\rm y = mx +b$

The slope of the line is 7 and point (1, 8),

Then,

The value of c is,

$\rm y = mx + c\\\\8 = 7(1) +c\\\\c = 8-7 \\\\c = 1$

Therefore,

The equation of the line is,

$\rm y = mx +b\\\\y = 7x+ 1$

Hence, The required equation of a line is $y = 7x+1$.

For more details refer to the link given below.

brainly.com/question/2564656

Answer 2

Answer:

y = 7x + 1

Step-by-step explanation:

y = mx + b and we know that m = 7. Put the values of x and y into the equation and solve for b.

8 = 7(1) + b

8 = 7 + b

1 = b

y = 7x + 1