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Contact [7]
3 years ago
6

What is the equation of a line with a slope of 7 and a point (1, 8) on the line? Express the equation in the form of ​ y=mx b

​ , where m is the slope and b is the y-intercept. Enter your answer in the box.
Mathematics
2 answers:
stepan [7]3 years ago
4 0

The equation of a line is y = 7x+1.

Given that,

The slope of the line is 7 and a point (1, 8) on the line.

We have to find,

The equation of the line is in the form of \rm y = mx +c.

According to the question,

The standard form of the equation having slope m and y in the intercept can be written as,

\rm y = mx +b

The slope of the line is 7 and point (1, 8),

Then,

The value of c is,

\rm y = mx + c\\\\8 = 7(1) +c\\\\c = 8-7 \\\\c = 1

Therefore,

The equation of the line is,

\rm y = mx +b\\\\y = 7x+ 1

Hence, The required equation of a line is y = 7x+1.

For more details refer to the link given below.

brainly.com/question/2564656

kompoz [17]3 years ago
4 0

Answer:

y = 7x + 1

Step-by-step explanation:

y = mx + b and we know that m = 7. Put the values of x and y into the equation and solve for b.

8 = 7(1) + b

8 = 7 + b

1 = b

y = 7x + 1

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Answer:

D

Step-by-step explanation:

I believe D is the answer because 10^-3 = 0.001 ; there is only one answer that has 0.001 in the correct exponential form (10^-3).

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