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3 years ago

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What is the equation of a line with a slope of 7 and a point (1, 8) on the line? Express the equation in the form of â€‹ y=mx b

â€‹ , where m is the slope and b is the y-intercept. Enter your answer in the box.

2 answers:

stepan [7]3 years ago

4 0

The equation of a line is $y = 7x+1$ .

Given that,

The slope of the line is 7 and a point (1, 8) on the line.

We have to find,

The equation of the line is in the form of $\rm y = mx +c$ .

According to the question,

The standard form of the equation having slope m and y in the intercept can be written as,

$\rm y = mx +b$

The slope of the line is 7 and point (1, 8),

Then,

The value of c is,

$\rm y = mx + c\\\\8 = 7(1) +c\\\\c = 8-7 \\\\c = 1$

Therefore,

The equation of the line is,

$\rm y = mx +b\\\\y = 7x+ 1$

Hence, The required equation of a line is $y = 7x+1$ .

For more details refer to the link given below.

brainly.com/question/2564656

kompoz [17]3 years ago

4 0

Answer:

y = 7x + 1

Step-by-step explanation:

y = mx + b and we know that m = 7. Put the values of x and y into the equation and solve for b.

8 = 7(1) + b

8 = 7 + b

1 = b

y = 7x + 1

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Kamila [148]

Answer:

Step-by-step explanation:

It is a solution because if you plug in 84 for b you get 84/12 = 7

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3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

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3 years ago

Find the slope between the given two points (2, 1) and (8, 9)

Juliette [100K]

Answer:

4/3

Step-by-step explanation:

9-1/8-2=

8/6=4/3

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None of the triangles listed has two equal base angles or two equal side lengths, therefore: D. No triangle is isosceles.

<h3>Properties of an Isosceles Triangle</h3>

An isosceles triangle has two base angles having equal angle measure.
The side lengths that are opposite each of the equal base angles are also congruent to each other.

Thus, none of the triangles listed has two equal base angles or two equal side lengths, therefore: D. No triangle is isosceles.

Learn more about isosceles triangle on:

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3 years ago

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3 years ago

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