2/3y-2/5=5
We move all terms to the left:
2/3y-2/5-(5)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
determiningTheFunctionDomain
2/3y-5-2/5=0
We calculate fractions
There is no solution for this equation
Answer:
W=0.8333*t
2.917 ft³
Step-by-step explanation:
At time t=3, there is 2.5 ft³ of water in the tub
Finding the relation will be;
3=2.5
1=?
Rate=0.8333 ft³/min
W=0.8333 ft³ / min
W=0.8333*t
At t=3.5 will be;
1 min = 0.8333
3.5 min =?
Apply cross-production
3.5*0.8333 =2.917 ft³
40%=0.4
0.4+1=1.4
4.5(1.4)=6.3
The answer is $6.30
For this case we have the following vectors:

The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
Answer:
The product point of the vectors a and b is:
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