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Dvinal [7]
3 years ago
5

A tunnel is in the shape of a parabola. The maximum height is 16 m and it is 16 m wide at the base, as shown below.

Mathematics
2 answers:
deff fn [24]3 years ago
7 0
The basic formula of a parabola is;

y -k= 4a (x-h)^2

Solving for this, the vertical clearance 7m forom the edge of the tunnel must be

15.7m

Hope this helps! Goodluck!

NeX [460]3 years ago
3 0
Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4

y=ax^2→y=-(1/4)x^2

7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4

Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m

Please, see the attached file.

Answer: Third option 15.75 m

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Maru [420]

Step-by-step explanation:

5⁰= 1

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1/8

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8 0
3 years ago
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Ivanshal [37]

The coordinates of the point intersection of lines (-1, -1)

If you want solve:

y = -2x - 3, y = 3x + 2

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Put the value of x to the first equation:

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3 0
3 years ago
In the standard (x, y) coordinate plane, what is the distance, in coordinate units, between (-3, -2) and (5, 5)?
Sav [38]

Answer:

10.630

Step-by-step explanation:

\sqrt(x_{2}  -x_{1})^{2} + (y_{2} -y_{1})^{2}

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113

\sqrt113

10.630


I hope this helps

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Varvara68 [4.7K]
We can find out he answer to the question by using the information given.
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