A tunnel is in the shape of a parabola. The maximum height is 16 m and it is 16 m wide at the base, as shown below.
2 answers:
Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
You might be interested in
answer in picture
stay safe (..
Answer:
1. x= 3y+6/2
y=2/3x-2
2.x=−y+3
y=−x+3
Step-by-step explanation:
1. Let's solve for x.
y=2/3x-2
Step 1: Flip the equation.
2/3x-2=y
Step 2: Add 2 to both sides.
2/3x-2+2=y+2
2/3x=y+2
Step 3: Divide both sides by 2/3.
2/3x/2/3=y+2/2/3
x= 3y+6/2
Let's solve for y.
y=2/3x-2
2. Let's solve for x.
y=−x+3
Step 1: Flip the equation.
−x+3=y
Step 2: Add -3 to both sides.
−x+3+−3=y+−3
−x=y−3
Step 3: Divide both sides by -1.
-x/-1=y-3/-1
x=−y+3
Let's solve for y.
y=−x+3
here are two graphs if you need a better explanation
HOPE THIS HELPS
