Yes the sailfish can swim one mile
Answer:
Below
Step-by-step explanation:
● x-20 = y+20 (1)
● 2(y-22) = x+22 (2)
This is a system of simulataneous equations
Let's simplify the expressions first
● x -20 = y + 20 (1)
Add 20 to both sides
● x -20 + 20 = y+20 +20
● x = y + 40 (1)
● 2(y-22) = x+22 (2)
● 2y - 44 = x +22
Substrat 22 from both sides
● 2y-44-22 = x+22-22
● 2y -66 = x (2)
This is the new system:
● x = y+40 (1)
● x = 2y-66 (2)
Substract (2) from (1)
● x-x = y+40-(2y-66)
● y+40-2y+66 = 0
● -y +106 = 0
● y = 106
Replace y with 106 in (1)
● x = y +40
● x = 106+40
● x = 146
So the solutions are (146,106)
<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
radius of small circle = 16 m
radius of large circle is doubled so it will be 32 m
Area of the larger circle = π x 32^2 = 1,204π m^2
answer
1,204π m^2
Answer:
1 sas 2 sas 3 asa 4 sas 5 ssa 6 ssa
