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Gennadij [26K]
3 years ago
11

If a sample of 99 bowlers were taken from a population of 466 bowlers,x could refer to the mean of how many bowlers scores

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

99

x is a mean of 99 bowlers scores

Step-by-step explanation:

Sample mean x is the mean of data samples taken from a population.

x is the sample mean

Number of population = 466

Number of samples = 99

Since, x is the mean of data samples, then x is the mean of the 99 sample data taken.

Therefore, x is a mean of 99 bowlers scores.

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According to the ASA theorem, which of the following sets of relationships can be used to show that VRT and STR are congruent?
irina [24]

Answer:

C. ∠SRT≅∠VTR and ∠STR≅∠VRT

Step-by-step explanation:

Given:

Quadrilateral is a parallelogram.

RS║VT; RT is an transversal line;

Hence By alternate interior angle property;

∠SRT≅∠VTR

∠STR≅∠VRT

Now in Δ VRT and Δ STR

∠SRT≅∠VTR (from above)

segment RT= Segment RT (common Segment for both triangles)

∠STR≅∠VRT (from above)

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Δ VRT ≅ Δ STR

Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT

7 0
2 years ago
John buys 3 pounds of cherries and 2 pounds of bananas he pays a total of $24.95 the bananas cost $6.50 less per pound than the
Murrr4er [49]

John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.

Let: b=cost of banana per pound and c=cost of cherries per pound

Equation 1: For 3 pounds of cherries and 2 pounds of bananas, John pays a total of $24.95.

3c + 2b =$24.95

Equation 2: The cost of bananas is $6.50 less than a pound of cherries.

b= c - $6.50

We can substitute the second equation into the first one to solve for the cost of cherries per pound.

3c + (2)(c-$6.50)= $24.95

3c + 2c -$13.00 = $24.95

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Substituting the value of c to the second equation to solve for b.

b= $7.59 - $6.50 = $1.09

The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.

For more information regarding the system of equations, please refer to brainly.com/question/25976025.

#SPJ4

4 0
1 year ago
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