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goldenfox [79]
3 years ago
7

It is given that trapezoid EFGH is an isosceles trapezoid. We know that FE ≅ GH by the definition of

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

1. isosceles trapezoid

2.  FEH

3.  GHE

4. Reflexive

5. SAS

Step-by-step explanation:

Edg2020!!

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Consider two functions: g(x)=−x2−6x and the quadratic function ​f(x)​ shown in the table.
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Answer:

Hence average rate of change is greater for f(x) in (0,3).

Yes. f(x) is greater than g(x) in the interval (0,3)

Yes. g(3) <f(3)


Step-by-step explanation:

To find average rate of change of f and g in (0,3)

f(3)-f(0)/3 = (9-0)/3 =3

g(3) = -9-18 = -27

g(0) = 0

Rate of change in(0,3) of g(x) = -27/3 =-9

Hence average rate of change is greater for f(x) in (0,3)

---

Both f and g have intercepts of y as 0

Hence both are equal.

3) Yes. f(x) is greater than g(x) in the interval (0,3)

Because g(x) <0 for all x in (0,3) while f(x) >0

4) g(3)= -9-18=-27 <f(3)



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14-5+20÷2∧2+4

exponent first: 14-5+20÷4+4

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add all: 14+4 = 18

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Question 5, x could be either 6 or -1.

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SashulF [63]
<h2><u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>

Given system of linear equations are ,

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And we need to find the Solution of the linear equation . So let's Firstly number the equations .

\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}

<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

=> y = 2

<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

<h3><u>★</u><u> </u><u>Hence</u><u> the required solution is ( 0 , 2 ) .</u></h3>
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Step-by-step explanation:

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