Given that car B travelled 5 mph slower than car A, let the rate (R) at which car B travelled be x, then the rate at which car A travelled is given by x + 5.
Given the formular RT = D, then the distance travelled by car A is given by 4(x + 5) and the distance travelled by car B is given by 4.5x.
Given that both cars travel an equal distance, then 4(x + 5) = 4.5x
4x + 20 = 4.5x
4.5x - 4x = 20
0.5x = 20
x = 20 / 0.5 = 40
Therefore, car B travel at 40 mph.
Answer:
I think that the selected answer is correct
Step-by-step explanation:
Okay so what f(3) is saying is that x=3. You have to plug three in for x to make the new equation of 2(3)^3-3(3)+1 next you would do pemdas which is parethesis then exponets then multiplication/division then addition/subtraction to get 2*3=6 6^3 is 216 216-3*3 is 207 207+1 is 208 so the answer is f(3)=208
Calculate the angles, use a scientific calculator
Step-by-step explanation:
give some hint
but I think the answer should be 8