Given two functions are
f(x) = 2 cos(x)
g(x) = 3 sin(x+ )
We know that the maximum value of cos x and sin x is always 1
y= maximum of cos = 1
y= maximum of sin =1
f(x) = 2 cos(x)
y= 2 (max of cos) = 2(1) = 2
g(x) = 3 sin(x+ )
y= 3 (max of sin) = 3(1) = 3
g(x) = 3 sin(x+ ) has the maximum value.
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Answer:
(b) (x – 4)^2 + (y – 6)^2 = 16
Step-by-step explanation:
The equation for a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
You want the equation for a circle with center (4, 6) and radius 4. That equation is ...
(x -4)^2 +(y -6)^2 = 16
Answer:
there is a 26 out of 52 of a chance
Step-by-step explanation:
4 prints
12x = 2.5x + 38
at 4, these expressions are equal