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3 years ago

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Find the volume of a cylinder with a diameter of 8 inches and a height that is three times the radius. Use 3.14 for pi and round

your answer to the nearest hundredth. (Hint: You may only enter numerals, decimal points, and negative signs in the answer blank)

2 answers:

dem82 [27]3 years ago

6 0

Do the volume of a circle then multiply by the length of the cylinder
area of a circle = $\pi r^2$
diameter/2 = radius
so 4^2 = 16 16*3.14 = 50.24
50.24*(4*3) = 50.24*12 = 602.88

joja [24]3 years ago

5 0

Answer:

602.88 sq in

Step-by-step explanation:

The formula for the volume of a cone is

V = πr²h

The diameter is 8; since the radius is half of the diameter, this makes the radius 8/2 = 4.

This gives us

V = 3.14(4²)h

We know the height is three times the radius this makes it 4(3) = 12:

V = 3.14(4²)(12) = 602.88

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The answer I got for this problem was 10.8 (multiplied 18 and 60 then divided by 100) however, it stated that my answer is incor

Delicious77 [7]

9514 1404 393

Answer:

30 mL

Step-by-step explanation:

The meaning of 60% solution is ...

alcohol/(total volume) = 0.60

You are told the amount of alcohol is 18 mL, so you have ...

(18 mL)/(total volume) = 0.60

Multiplying by total volume gives ...

18 mL = 0.60 × (total volume)

Then dividing by 0.60, you have ...

(18 mL)/0.60 = total volume = 30 mL

_____

<em>Additional comment</em>

You need to apply what you know about the real world to consider whether your answer makes any sense. If alcohol is a little more than half of the volume, and the amount of alcohol is 18 mL, then the total volume cannot be less than 18 mL. In fact, you expect it to be not quite double 18 mL.

An answer of 10.8 mL makes no sense in this context. You cannot have less total solution than you have of something that makes up a part of the total solution.

7 0

3 years ago

Find the fifth term of a sequence whose first term is 8 and common ratio is 3/2

Arlecino [84]

Answer:

Option c. 81/2

Step-by-step explanation:

Fifth term: a5=?

First term: a1=8

Common ratio: r=3/2

an=a1*r^(n-1)

with n=5

a5=a1*r^(5-1)

a5=a1*r^4

Replacing the known values:

a5=8*(3/2)^4

a5=8*(3)^4/(2)^4

a5=8*81/16

Simplifying: Dividing the numerator and denominator by 8:

a5=(8*81/8)/(16/8)

a5=81/2

Answer: Option c. 81/2

3 0

4 years ago

What is the sum of ? <br><br>I will put a pic if the answer is correct ill mark brainlist

olga2289 [7]

$\text{The sum of } 1\frac{7}{10} \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}$

<em><u>Solution:</u></em>

Given that we have to find the sum of $1\frac{7}{10} \text{ and } 3\frac{3}{5}$

<em><u>Let us first convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

Therefore,

$1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}$

Now we can add both the fractions

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18}{5}$

Make the denominators same

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}$

Now convert the fraction to mixed number

When we divide 53 by 10 , the remainder is 3

Therefore, write 5 as a whole number and and 3 as numerator and 10 as denominator

$\frac{53}{10} = 5\frac{3}{10}$

Thus the sum of given mixed fraction is $5\frac{3}{10}$

6 0

3 years ago

Directions: Find the volume of each figure. Round to the nearest tenth if necessary.

balu736 [363]

Answer:

Step-by-step explanation:

square-based pyramid:

volume V = (⅓)b²h

= (⅓)7²·16

≅ 261.3 ft³

:::::

Can't help with question 3. I haven't learned triangle-based pyramids.

:::::

cone:

volume V = ⅓πr²h

= ⅓π17²·20

= 6052.8 yd³

:::::

can't help with question 7. Never did this kind of pyramid.

3 0

3 years ago

A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.

kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

$C = Children; S = Students; A = Adults$

For the capacity, we have:

$C + S + A = 329$

For the tickets sold, we have:

$5C + 7S + 12A = 2388$

Half as many as adults are children implies that:

$A = \frac{C}{2}$

Required

Solve for A, C and S

The equations to solve are:

$C + S + A = 329$ -- (1)

$5C + 7S + 12A = 2388$ -- (2)

$A = \frac{C}{2}$ -- (3)

Make C the subject in (3)

$C = 2A$

Substitute $C = 2A$ in (1) and (2)

$C + S + A = 329$ -- (1)

$2A + S + A = 329$

$3A + S = 329$

Make S the subject

$S = 329 - 3A$

$5C + 7S + 12A = 2388$ -- (2)

$5*2A + 7S + 12A = 2388$

$10A + 7S + 12A = 2388$

$7S + 22A = 2388$

Substitute $S = 329 - 3A$

$7(329 - 3A) + 22A = 2388$

$2303 - 21A + 22A = 2388$

$2303 +A = 2388$

Solve for A

$A = 2388 - 2303$

$A = 85$

Recall that: $C = 2A$

$C = 2 * 85$

$C = 170$

Recall that: $S = 329 - 3A$

$S = 329 - 3 * 85$

$S = 329 - 255$

$S = 74$

Hence, the result is:

$C = 170$

$S = 74$

$A = 85$

8 0

3 years ago