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stiv31 [10]
2 years ago
9

I really need help with this question so can you tell me the answer please

Mathematics
1 answer:
LenaWriter [7]2 years ago
8 0

Answer:

x=1.7320508075688...... equal to 1.73

Step-by-step explanation:

equation is: y=x*x+1

so put 4 instead of y

4=x*x+1

so x*x=3

x=1.7320508075688......

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What is the slope of line m?
maxonik [38]

Answer:

Slope= -0.5

Step-by-step explanation:

3 0
3 years ago
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Direction: Determine whether the given point is a solution to the given system of linear inequalities.
Ann [662]

Answer:

The given point is a solution to the given system of inequalities.

Step-by-step explanation:

Again, we can substitute the coordinates of the given point into the system of inequalities. We know that the x-coordinate and y-coordinate of (3,2) are x=3 and y=2, respectively.

Plugging these values into the first inequality, y\leq x+3, gives us 2\leq 3+3, which simplifies to 2\leq 6. This is a true statement, so the given point satisfies the first inequality. We still need to check if it satisfies the second inequality though, because if it doesn't, it won't be a solution to the system.

Plugging the coordinates into the second inequality, y\geq -x+3, gives us 2\geq -3+3, which simplifies to 2\geq 0. This is also a true statement, so the given point satisfies the second inequality as well. Therefore, \bold(\bold3\bold,\bold2\bold) is a solution to the given system of inequalities since it satisfies all of the inequalities in the system. Hope this helps!

8 0
3 years ago
Can someone help me please
Xelga [282]

Answer:

8<u>></u>x<u>></u>=4

this is the answer.

4 0
3 years ago
A marble tile measures 20 cm by 15 cm.how many tiles will be required to cover a wall of size 5m by 3m?
Rainbow [258]
First, we get the area of each tile: (100 cm = 1m)
.20 m* .15 m = 0.03m^2
Then, we solve for the total area of the wall:
5m*3m= 15m^2
Then we divide 
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5 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
3 years ago
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