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2 years ago

I really need help with this question so can you tell me the answer please

Mathematics

1 answer:

LenaWriter [7]2 years ago

8 0

Answer:

x=1.7320508075688...... equal to 1.73

Step-by-step explanation:

equation is: y=x*x+1

so put 4 instead of y

4=x*x+1

so x*x=3

x=1.7320508075688......

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Someone help me. ty

-Dominant- [34]

Answer:

Step-by-step explanation:

7 0

3 years ago

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Enter the correct answer in the box. What is this expression in simplified form? <br> 3\sqrt{88}

Ugo [173]

Answer: $12\sqrt{5}$

Step-by-step explanation:

$3\sqrt{88}$

88 can be rewritten as 8 x 10 and 8 can be rewritten as $2^2*2$ making a 2 come out of the root.

$3\sqrt{2^2*2*10}\\ 3*2\sqrt{2*10}\\6\sqrt{2*10}$

10 can be rewritten as 2 x 5.

$6\sqrt{2*2*5}$

2*2 can also be rewritten as $2^2$ making a 2 come out of the root.

$6\sqrt{2^2*5}\\ 6*2\sqrt{5}\\ 12\sqrt{5}$

We can't keep simplifying the root.

4 0

3 years ago

What is the total surface area of the rectangular<br> prism represented by this net?

dedylja [7]

Answer:

Total surface area of the rectangular prism is 150.88 cm^2

Step-by-step explanation:

area of base = area of top

area of base = 5 x 3.1 = 15.5 cm^2

Area of small lateral surface having dimensions 3.1 cm x 7.4 cm is

=3.1 x 7.4 = 22.94 cm^2

Area of big lateral surface having dimensions 5 cm x 7.4 cm is

=5 x 7.4 = 37 cm^2

Total area of prism = 2 x 15.5 + 2 x 22.94 + 2 x 37 = 150.88 cm^2

total surface area of the rectangular prism is 150.88 cm^2

7 0

3 years ago

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

THIS TOO GOD I NEED HELP SO BAD I DONT UNDERSTAND

Zina [86]

Answer:

54.7

Step-by-step explanation:

16.7 + 11 + 11 + 8 + 8 = 54.7

Note

I don't know how you are wrong but I showed my work and I got the same answer which is weird.

8 0

3 years ago