It will take <u>120 minutes</u> for the concentration to become > 15000 cells/cm³
<u>Given data:</u>
Initial concentration ( density ) = 1000 cells / cm³
Target/final concentration = > 15,000 cells /cm³
<h3 /><h3>Calculating the concentration every 30 minutes </h3><h3 />
<em>note</em><em> : Given that each cell divides every 30 minutes </em>
- <u>After the first 30 minutes </u>
Concentration = 2000 cells / cm³
concentration = 4000 cells / cm³
concentration = 8000 cells / cm³
- <u>After 120 minutes </u>
concentration = 16000 cells / cm³
Therefore after 120 minutes the concentration of the cells will be greater than 15000 cells/cm³ ( i.e. 16000 cells/cm³ )
Learn more about concentration : brainly.com/question/17206790
Answer:
Nesting & Foraging behavior
Explanation:
Seabirds are generally tertiary consumers and / or marine predators that, in marine foodwebs, occupy the upper trophic level. They are very well adapted to all marine ecosystems and feed on a variety of prey: from micro-crustaceans to fish and cephalopods.
Generally, seabirds are observed performing a nesting behavior, by laying eggs near the shore, and then are found exhibiting foraging behavior -searching and foraging for prey- in both the coastline and pelagic zone, also known as the open sea.
Seabirds exhibit different foraging behaviors, for example, the <u>surface feeding behavior which involves flying along the surface with their beak in the water. Gulls, albatrosses and petrels are examples of surface feeders.</u>
<u>On the other hand, plunge diving involves preying on fast marine organisms by diving into the water during their flight. Pelicans are example of seabirds who engage in this behavior.</u>
Since fish feeds primarily on large amphipod,
therefore what we expect to remain to evolve on ponds containing fish would be
smaller amphipod or crustacean. Then correct answer to this question would be:
<span>“Ponds with fish should have smaller amphipods.”</span>
D) #recombinant=116+601+4+2+113+625=1462
#nonrecombinant=2538+2708=5246
RF=R/(N+R)=1462/6708=0.2
E) I=1-Q
I-interference
Q-coefficient of coincidence
Q=O2Xo/E2xo(2xo-double crossovers)
O2xo=6
P=(distance from C1 to Sh/100)*(distance from Sh to Wx/100)
=(3.38/100)*(18.28/100)=0.006
E2xo=0.006*6708=40.248
Q=6/40.248=0.15
I=1-0.15=0.85
