Question

Find two positive consecutive integers such that the square of the first added to three times the second is 24

Answer 1

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

$x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6$

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.