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statuscvo [17]
3 years ago
13

Find two positive consecutive integers such that the square of the first added to three times the second is 24

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.

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(Photo attached) Trig question. I partially understand it, but not completely. Please explain! :) Thanks in advance.
aliya0001 [1]

Answer:

  • A = 2
  • B = 3

Step-by-step explanation:

You can start by recognizing 19/12π = π +7/12π, so the desired sine is ...

  sin(19/12π) = -sin(7/12π) = -(sin(3/12π +4/12π)) = -sin(π/4 +π/3)

  -sin(π/4 +π/3) = -sin(π/4)cos(π/3) -cos(π/4)sin(π/3)

Of course, you know that ...

  sin(π/4) = cos(π/4) = (√2)/2

  cos(π/3) = 1/2

  sin(π/3) = (√3)/2

So, the desired value is ...

  sin(19π/12) = -(√2)/2×1/2 -(√2)/2×(√3/2) = -(√2)/4×(1 +√3)

Comparing this form to the desired answer form, we see ...

  A = 2

  B = 3

5 0
3 years ago
What is the solution to the equation? 2 x squared plus 4 equals 20 Choose all answers that are correct.
Stolb23 [73]
2x^2+4=20\ \ \ \ |subtract\ 4\ from\ both\ sides\\\\2x^2=16\ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=8\iff x=\pm\sqrt8\\----------------------------\\\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\cdot\sqrt2=2\sqrt2\ \ \ |use\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\-----------------------------\\therefore\ your\ answer\ is\ -2\sqrt2\ and\ 2\sqrt2\to\boxed{a\ and\ c}
8 0
2 years ago
Given m||n, find the value of x.<br> +<br> 360<br> -Po
AVprozaik [17]

Answer:

Step-by-step explanation:

13.6

6 0
2 years ago
What is the sum of an 8-term geometric series if the first term is -11, the last term is 859,375, and the common ratio is -5?
NikAS [45]
Formula of the sum of the 1st nth term in a Geometric Progression:


Sum = a₁(1-rⁿ)/(1-r), where a₁ = 1st term, r = common ratio and n= rank nth of term (r≠1)

Sum = (-11)[1-(-5⁸)] /[(1-(-5)]

Sum = (-11)(1- 390625)/(6)


SUM = 716,144
3 0
3 years ago
How many solutions does this system of Equations have x-2y=2 y=-2x+5​
gayaneshka [121]

Answer:

One solution: x=2.4, y=0.2

Step-by-step explanation:

x-2y=2

y=-2x+5​

x-2(-2x+5)=2

x+4x-10=2

5x=2+10=12

x=12:5=2.4

y=-2x+5=-2*2.4+5=-4.8+5=0.2

3 0
3 years ago
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