Let 6x-3y=3 be equation 1 and -2x +6y=14 be equation 2.
Take 2 common from eq 2 let the optioned eq be equation number 3.
And solve eq number 1 and 3.
Area = length x width
Area = 21 square cm
Width = x
Length = 3x + 2
21 = 3x+ 2 * x
21 = 3x ^2 + 2x
Subtract 21 from both sides:
3x^2 + 2x -21 = 0
Use the quadratic formula to solve for x:
-2 +/- sqrt(2^2-4*3(-21))/(2*3)
X = 7/3 and -3
A dimension can’t be a negative value so x needs to be 7/3
Width = x = 7/3 = 2 1/3 cm
Length = 3(7/3) + 2 = 9 cm
Check: 9 x 2 1/3 = 21
Dimensions: width 2 1/3 cm length 9 cm
Answer:
2/1
Step-by-step explanation:
x1=1 ,y1=3
x2=2 , y2=5
then
m= 5-3/2-1= 2/1
Answer:
16.66
17.(8× + 2)° (4× + 4)°
Step-by-step explanation:
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