For f(x) = 2x² + 3x-10 and g(x) = 3(x-2) find fog (3)

1 answer:

4 0

(f o g) = 2(3x - 6)^2 + 3(3x - 6) - 10
(f o g) = 2(9x^2 - 36x + 36) + 9x - 18 - 10
(f o g) = 18x^2 - 72x + 72 + 9x - 28
(f o g) = 18x^2 - 63x + 44

(f o g)(3) = 18(3)^2 - 63(3) + 44
= 162 - 189 + 44
= -27 + 44
= 17

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Given a 30-60-90 triangle with a long<br> leg of 9 in, determine the length of the<br> hypotenuse.

aniked [119]

Answer:

10.38 in

Step-by-step explanation:

Long side would be opposite to 60°.

Since, side opposite to 60° is root 3 upon 2 times of hypotenuse.

$9 = \frac{ \sqrt{3} }{2} \times hypotenuse \\ \\ hypotenuse = \frac{9 \times 2}{ \sqrt{3} } \\ = \frac{18}{ \sqrt{3} } = \frac{18 \sqrt{3} }{3} = 6 \sqrt{3} = 6 \times 1.73 \\ \: \: \: \red{ \bold{hypotenuse = 10.38 \: in}}$