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3 years ago

For f(x) = 2x² + 3x-10 and g(x) = 3(x-2) find fog (3)

1 answer:

4 0

(f o g) = 2(3x - 6)^2 + 3(3x - 6) - 10
(f o g) = 2(9x^2 - 36x + 36) + 9x - 18 - 10
(f o g) = 18x^2 - 72x + 72 + 9x - 28
(f o g) = 18x^2 - 63x + 44

(f o g)(3) = 18(3)^2 - 63(3) + 44
= 162 - 189 + 44
= -27 + 44
= 17

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kvv77 [185]

Answer:

1/2 the area of the quadilateral ABCD

Step-by-step explanation:

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3 years ago

Let f(x) = x^2 + 6x.

rusak2 [61]

Answer:

(A) The slope of secant line is 18.

(B) The slope of secant line is h+16.

Step-by-step explanation:

(A)

The given function is

$f(x)=x^2+6x$

At x=3,

$f(3)=(3)^2+6(3)=27$

At x=9,

$f(9)=(9)^2+6(9)=135$

The secant line joining (3,27) and (9,135). So, the slope of secant line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{135-27}{9-3}=18$

The slope of secant line is 18.

(B)

The given function is

$f(x)=x^2+6x$

At x=5,

$f(5)=(5)^2+6(5)=55$

At x=5+h,

$f(5+h)=(5+h)^2+6(5+h)=h^2 + 16 h + 55$

The secant line joining (5,55) and $(5+h,h^2 + 16 h + 55)$ . So, the slope of secant line is

$m=\dfrac{h^2 + 16 h + 55-55}{5+h-5}$

$m=\dfrac{h^2 + 16 h }{h}$

$m=h+16$

The slope of secant line is h+16.

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3 years ago

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OlgaM077 [116]

A. -23

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3 years ago

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artcher [175]

A vertical translation 1 unit down since for example x is 1, if u plug it in both equations it is f(1)=1*2-1 which equals f(1)=1 and the point is (1,1) for the other one, g(1)=(1-1)2-1 it equals g(1)=-1

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3 years ago

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Natasha_Volkova [10]

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