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krek1111 [17]
2 years ago
7

A store sells laptops for $720 each. This price is 20 percent more than what it cost the store to buy each of them. Before the n

ext model's release, store employees can purchase any remaining laptops at 23% off the store's cost. How much would it cost an employee to purchase one of these laptops at the sale? PLS HELP
Mathematics
2 answers:
Pani-rosa [81]2 years ago
7 0

It would cost an employee $443.52 to purchase one of these laptops at the sale.

The selling price of the laptops is $720 each. The cost price is 20 percent more than the cost price.

Cost price = Selling price - 20% of cost price

Cost price = 720 - 20% * 720 = $576

At the release, the laptops are at 23% off the store's cost. Hence:

Price of laptop at release = 576 - 23% of 576

Price of laptop at release = $443.52

It would cost an employee $443.52 to purchase one of these laptops at the sale.

Find out more at: brainly.com/question/20286603

Yuliya22 [10]2 years ago
5 0

Answer:

462

Step-by-step explanation:

I do RSM its correct

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dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

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Answer:

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