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stiks02 [169]
3 years ago
12

Simplify: x36y64‾‾‾‾‾‾√

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

Step-by-step explanation:

x18y32 x18y ​x6y4 ​x6y32

​

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PLS HELP ME! Write a rule (function) for the data in this table.
yKpoI14uk [10]

Answer:

y = x - 3

<h3>How I know I'm correct:</h3>

if you plug in the numbers from the table, it checks out.

y = x - 3

0 = 3 - 3

0 = 0

y = x - 3

1 = 4 - 3

1 = 1

y = x - 3

2 = 5 - 3

2 = 2

and so on

5 0
4 years ago
What is the awnser to 48 - (-12)
valkas [14]
I got 48-(-12) equals to 60
3 0
4 years ago
Read 2 more answers
A triangle with vertices at A(20, –30), B(10, –15), and C(5, –20) has been dilated with a center of dilation at the origin. The
WARRIOR [948]

Answer:

The correct answer is 5.

Step-by-step explanation:

This is because if you divide 10 by 2 and -15 by 3

you get 5. Now to double check, you can do 10/5 and -15/5

This will give you 2, -3, which is the coordinates.


Hope this helps!

6 0
4 years ago
Read 2 more answers
M( -6, 4) is the midpoint of RS. If S has coordinates (-3, 10), find the coordinates of R.
poizon [28]

Answer:

Coordinate of R is (-9, -2)

Step-by-step explanation:

Given

M (-6, 4)

S (-3, 10)

Distance between M and S are x = 3  y = 6

Since M is the midpoint between RS, such that distance between RM = MS

x = -6 - 3 = - 9

y = 4 - 6 = - 2

6 0
3 years ago
A well known pharmaceutical manufacturer is manufacturing a newly developed vaccine, and is concerned about variability in the i
Lana71 [14]

Answer:

a

The  null hypothesis is H_o :  \  \sigma^2 =  1.9

The alternative hypothesis is  H_a :  \  \sigma^2 \ne 1.9  

b

 X^2 =  13.74

c

The decision rule is  

Reject the null hypothesis

d

The conclusion is  

There is no sufficient evidence to conclude that the variance of the immune response is equal to 1.9.

Step-by-step explanation:

From the question we are are told that

   The variance is \sigma ^2 =  1.9

    The sample size is  n =  30  

    The  sample variance  is  s^2 = 0.9

    The level of significance is  \alpha  =  0.05

   

The  null hypothesis is H_o :  \  \sigma^2 =  1.9

The alternative hypothesis is  H_a :  \  \sigma^2 \ne 1.9  

Generally the test statistics  is mathematically represented as

          X^2 = \frac{ (n- 1 ) * s^2 }{ \sigma^2 }

=>       X^2 = \frac{ (30 - 1 ) * 0.9 }{1.9  }

=>       X^2 =  13.74

Generally  from the degree of freedom is mathematically represented as

         df =  n- 1

=>      df =   30 - 1

=>      df =   29

Generally from the chi distribution table the critical value of  \frac{\alpha}{2}  \   and  \   1 - \frac{ \alpha }{2} at a degree of freedom  of  df =   29 is  

       X^2 _{ \frac{\alpha }{2} ,  df } =  X^2 _{ \frac{0.05 }{2}  , 29 }  =  45.7

=>     X^2 _{ 1 - \frac{\alpha }{2} ,  df } =  X^2 _{1 -  \frac{0.05 }{2}  , 29 }  =  16.0 5

Gnerally from the values obtained we see that

         X^2 <  X^2 _{ 1 - \frac{\alpha }{2}  ,  df } hence

The decision rule is  

Reject the null hypothesis

The conclusion is  

There is no sufficient evidence to conclude that the variance of the immune response is equal to 1.9.

6 0
3 years ago
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