Answer:
69.08
Step-by-step explanation:
circumference is 2πr which is 3.14 x 2 x 11
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 330, \sigma = 12](https://tex.z-dn.net/?f=%5Cmu%20%3D%20330%2C%20%5Csigma%20%3D%2012)
a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![0.842 = \frac{X - 330}{12}](https://tex.z-dn.net/?f=0.842%20%3D%20%5Cfrac%7BX%20-%20330%7D%7B12%7D)
![X - 330 = 12*0.842](https://tex.z-dn.net/?f=X%20-%20330%20%3D%2012%2A0.842)
![X = 340.1](https://tex.z-dn.net/?f=X%20%3D%20340.1)
Weights of at least 340.1 are in the highest 20%.
Find the median first. The middle of all the numbers.
5, 7, 8, 10, 11, 13, 14, 18, 27
11 is the median.
Then find the median of the upper quartile.
The upper quartile consists of numbers...
5, 7, 8, 10
Since it is an even set of numbers add the two in the middle and divided by two. So 7 plus 8= 15/2.
7.5 is your upper quartile.
Answer:
Alternate exterior
Step-by-step explanation:
They are on opposite sides and both exterior
Answer:
14
Step-by-step explanation:
28=Diameter
Radius= D/2
=14