The bulldog soccer team wants to increase the size of its

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

4 0

2 years ago

The function g(x) = 10x2 – 100x + 213 written in vertex form is g(x) = 10(x – 5)2 – 37. Which statements are true about g(x)? Se

9966 [12]

Answer:

The vertex of the graph is (5, -37) [see attached image]
The parabola has a minimum [the coefficient of x² is positive]
The parabola opens up [the coefficient of x² is positive]

3 0

1 year ago

If you know that 7 - square root 5 is it root of a polynomial function

Kitty [74]

Answer:

As you must know, If one root of the polynomial 7-√5, the other will be 7+√5 i.e irrational root occur in pairs.

A polynomial function cannot have single unreal i.e irrational root. It always occur in pairs.

So , consider a polynomial function of any degree, if it has a root 7-√5, then it must have another root as 7+√5.

A polynomial can't have 7-√5 as a single root.

4 0

3 years ago

62% of trees were saved from a fire. If this represents 1420 trees, how many trees were originally in the forest?Round to the ne

tresset_1 [31]

Answer:

2290 trees

Step-by-step explanation:

Given data

Let the total number of trees be x

62% of the total trees x is 1420 trees

mathematically

62/100x= 1420

0.62x= 1420

divide both sides by 0.62

x= 1420/0.62

x= 2290.32

To the nearest whole tree= 2290 trees

5 0

2 years ago

This is confusing i need help ;-;

katovenus [111]

Answer:

B I think

Step-by-step explanation:

5 0

3 years ago

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