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katrin [286]
3 years ago
5

What is the relationship between impulse and momentum.

Physics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

I= ∆P that means (impulse= change in momentum)

Explanation:

impulse= force× time

momentum=mass × volume

so basically both formulas are equal to each other

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I believe it is 
B)The Sun is closer than Deneb


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3 years ago
A raging bull of mass 700kg runs at 10 m/s. How much kinetic energy does it have?
Illusion [34]

Answer: 35000 J or 35kJ

Explanation:

Use equation for kinetic energy : Ek=mV²/2

m=700 kg

V=10m/s

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Ek= 700kg*100m²7s²/2

Ek=35000 J=35kJ

6 0
4 years ago
Which best explains why the shape of a liquid can change? (1 point) a The particles have just enough energy to move past each ot
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3 years ago
Read 2 more answers
9. During an egg toss, a catcher must cushion the egg by maximizing the time it takes to stop the
Lorico [155]

Answer:

the impulse experienced by the egg is 0.053 kgm/s.

Explanation:

Given;

mass of the egg, m = 60 g = 0.06 kg

initial velocity of the egg, u = 6 m/s

height moved by the egg, h = 50 cm = 0.5 m

Determine the final velocity of the egg as it moves upward;

v² = u² + 2(-g)h

v² = u² - 2gh

where;

v is the final velocity

-g is negative acceleration due gravity as it moves upward

v² = 6² - 2(9.8 x 0.5)

v² = 26.2

v = √26.2

v = 5.12 m/s

The impulse applied to the egg is the change in linear momentum;

J = ΔP

ΔP = mu - mv

ΔP = m(u - v)

ΔP = 0.06(6 - 5.12)

ΔP = 0.053 kgm/s

Therefore, the impulse experienced by the egg is 0.053 kgm/s.

8 0
3 years ago
14. A ball initially at rest rolls without slipping
elena-s [515]

Answer:

v = √(10gh/7)

Explanation:

Initial gravitational energy = final rotational energy + kinetic energy

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For a solid sphere, I = ⅖ mr².

For rolling without slipping, ω = v/r.

mgh = ½ (⅖ mr²) (v/r)² + ½ mv²

mgh = ⅕ mv² + ½ mv²

mgh = 7/10 mv²

10/7 gh = v²

v = √(10gh/7)

7 0
3 years ago
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