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Eva8 [605]
3 years ago
15

Write this number using digits six million, ninety thousand three

Mathematics
2 answers:
alexira [117]3 years ago
8 0
The answer on the image would be 40,065.

The answer for the question being asked is 6,090,003.

To find the problem you have you would sort each number in a certain level. For 6 million it would be sorted into the one million because it is a single digit in the million. The 90 thousand would be sorted into the 10 thousands because it is not over 100 thousand. Next would be 3 which is just a single number where you would put at the end.
bixtya [17]3 years ago
3 0

Answer:

6090003

Step-by-step explanation:

6090003

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what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
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The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

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